Sonar, originally an <span>acronym for SOund Navigation And Ranging
</span>a technique that uses sound<span> propagation.</span>
The court of international trade, because tariffs are taxes upon trade
Answer:
B = - 1.51 10⁻⁷ T
Explanation:
For this exercise we can use Faraday's law of induction
E = - 
In this case, they indicate that the normal and the magnetite field are in the same direction, so the angle is zero (cos 0 = 1), they give the area of the loop A = 4.32 10⁻⁴ m² and since we have N = 1470 turns in each one a voltage is induced
E = - N B A
B = -E A / N (1)
we find the induced voltage with ohm's law
V = i R
where the current is defined by
i = Q / t
we substitute
V = Q R / t
let's calculate
V = 9.18 10-3 56.0 / t
We must assume a time normally is t = 1 s
V = 0.514 V
this is the voltage in the circuit which must be the induced voltage V = E
we substitute in 1
B = - 0.514 4.32 10⁻⁴ / 1470
B = - 1.51 10⁻⁷ T
Answer:
a) 35.75 ft/s
b) 45 ft
Explanation:
<u>Given </u>
Weight W = 100 lbf
mass(m) = 100*32.174/32.2=99.92 lb
decrease in kinetic energy ΔKE = -500 ft.lbf
increase in kinetic energy ΔPE= 1500 ft.lbf
initial velocity V_1 = 40 ft/s
initial height h_1 = 30 ft/s
The gravitational acceleration g = 32.2 ft/s2 Required
(a) Final velocity V_2 (a) Final elevation h_2
<u>Solution </u>
Change in kinetic energy is defined by
ΔKE = .5*m *( V_2 ^2-V_1^2)
Change in potential energy is defined by
ΔKE = W *( h_2 -h_1 )
Then,
-500=.5*99.92*1/32.174*(V_2 ^2-40^2)
V_2=35.75 ft/s
1500 = 100 x (h_2 — 30)
h_2= 45 ft
Answer:
2.57 seconds
Explanation:
The motion of the ball on the two axis is;
x(t) = Vo Cos θt
y(t) = h + Vo sin θt - 1/2gt²
Where; h is the initial height from which the ball was thrown.
Vo is the initial speed of the ball, 22 m/s , θ is the angle, 35° and g is the gravitational acceleration, 9.81 m/s²
We want to find the time t at which y(t) = h
Therefore;
y(t) = h + Vo sin θt - 1/2gt²
Whose solutions are, t = 0, at the beginning of the motion, and
t = 2 Vo sinθ/g
= (2 × 22 × sin 35°)/9.81
= 2.57 seconds
