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Andrej [43]
3 years ago
9

Explain you own words why energy is considered to be naturals money. Give an example to support your explanation

Physics
1 answer:
max2010maxim [7]3 years ago
8 0

Answer:

because we naturally use energy everyday in everyway , energy is also a bill for instance you electric bill used by energy

Explanation:

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Assuming no air resistance, all projectiles have:
MaRussiya [10]

Answer: Option C

C) accelerated vertical motion and constant horizontal motion.

Explanation:

If there is no air resistance then during the projectile movement the only force that causes an acceleration is the gravitational force.

We know that this force produces an acceleration of 9.8 m / s ^ 2 in the projectile.

As the gravitational force attracts the object towards the earth, then the acceleration that this force produces is always in the vertical direction. In the horizontal direction the object is not accelerated (because there is no air resistance).

Therefore the correct answer is option C.

"accelerated vertical motion and constant horizontal motion".

4 0
2 years ago
A bullet of mass 0.107 kg traveling horizontally at a speed of 300 m/s embeds itself in a block of mass 3 kg that is sitting at
melisa1 [442]

Answer:

165.77J

Explanation:

M₁ = 0.107kg

u₁ = 300m/s

m₂ = 3kg

u₂ = 0

v =

m₁u₁ + m₂u₂ = (m₁ + m₂)V

(0.107*300) + 0 = (0.107 + 3)V

V = 32.1 / 3.107 = 10.33m/s

kinetic energy of the system after collision =

½m1v² + ½m2v²

K.E = ½(m1 + m2)v²

K.E = ½(0.107+3) * 10.33²

K.E = 165.77J

5 0
3 years ago
A particle with charge − 2.74 × 10 − 6 C −2.74×10−6 C is released at rest in a region of constant, uniform electric field. Assum
s2008m [1.1K]

Answer:

241.7 s

Explanation:

We are given that

Charge of particle=q=-2.74\times 10^{-6} C

Kinetic energy of particle=K_E=6.65\times 10^{-10} J

Initial time=t_1=6.36 s

Final potential difference=V_2=0.351 V

We have to find the time t after that the particle is released and traveled through a potential difference 0.351 V.

We know that

qV=K.E

Using the formula

2.74\times 10^{-6}V_1=6.65\times 10^{-10} J

V_1=\frac{6.65\times 10^{-10}}{2.74\times 10^{-6}}=2.43\times 10^{-4} V

Initial voltage=V_1=2.43\times 10^{-4} V

\frac{\initial\;voltage}{final\;voltage}=(\frac{initial\;time}{final\;time})^2

Using the formula

\frac{V_1}{V_2}=(\frac{6.36}{t})^2

\frac{2.43\times 10^{-4}}{0.351}=\frac{(6.36)^2}{t^2}

t^2=\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}

t=\sqrt{\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}}

t=241.7 s

Hence, after 241.7 s the particle is released has it traveled through a potential difference of 0.351 V.

6 0
3 years ago
What is the cost of conserved energy for compact fluorescent lighting?
jonny [76]
Typically use 25% -80% less energy than traditional
-incandescents, saves you money
-can last 3-25 times longer
7 0
3 years ago
Metallic bonds are important to how paperclips are both made and used. Which statement best describes how metallic bond properti
Vikentia [17]
<span>The statement that best describes how metallic bond properties are important for making and using paperclips is Ductility is important for making paperclips, and malleability is important for using them. 

Ductility is defined as the ability of the solid material to stretch under tensil stress. The metal of the paper clip is ductile when paperclips are made because the metal is stretch until it forms a wire.

Malleability is defined as the ability of the solid material to deform under pressure. Paperclips are very malleable. It can be manipulated into forming different shapes with the used of our hand strength.
</span>
3 0
4 years ago
Read 2 more answers
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