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3 years ago

what is the wavelength of radio waves transmitted by an FM station at 90MHz where 1M=10^6, and speed of radiowave is 3*10^8m/s

Physics

1 answer:

Igoryamba3 years ago

5 0

Answer:

λ = 3.33 m

Explanation:

<u><em>Given:</em></u>

Frequency = f = 9 × 10⁷ Hz

Speed = v = 3 × 10⁸ m/s

<u><em>Required:</em></u>

Wavelength = λ = ?

<u><em>Formula:</em></u>

v = fλ

<u><em>Solution:</em></u>

<em>Putting the givens in the formula</em>

v = fλ

λ = $\frac{v}{f}$

λ = $\frac{3*10^8}{9*10^7}$

λ = 0.33 × 10¹

λ = 3.33 m

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A boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s .

zimovet [89]

Answer:

Force exerted, F = 1.5 N

Explanation:

It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.

i.e. u = 0

v = 30 m/s

Time taken, t = 0.06 s

Mass of the paper, m = 0.003 kg

We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :

$F=m\times a$

$F=m\times (\dfrac{v-u}{t})$

$F=0.003\times (\dfrac{30}{0.06})$

F = 1.5 N

So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.

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3 years ago

When astronauts travel to the moon, their bodies experience a lower gravitational pull than on Earth. Which type of pull are the

postnew [5]

They are experiencing the pull of leaving the atmosphere

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4 years ago

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An object of mass 20g taken at a height of 2m above the ground. Which type of energy is possessed by the object at this height ?

In-s [12.5K]

<h3><u>Given</u> </h3>

Mass of an object is $\bf\red{20 g}$
Height of the body is $\bf\green{2 m}$

Value of the energy

<h3><u>Solution</u></h3>

${\purple {\underline{\boxed{\sf{ Potential\: Energy \:=\: mgh}}}}}$

Where,

$\sf\red{m}$ = Mass
$\sf\green{g}$ = Gravity
$\sf\blue{h}$ = Height

Now, Converting gram to kg

$\longrightarrow\:$ 1000g = 1kg

$\longrightarrow\:$ 20g = $\sf\dfrac{20}{1000}$

$\longrightarrow\:$ = 0.02 kg

According to the question

$\sf\red{Mass \:= \:0.02 kg}$

$\sf\green{Gravitational \;force \:= \;10 m/s^{2}}$

$\sf\purple{Height\: =\: 2 m}$

Putting these values

$\to\:$ Potential Energy = mgh

$\to\:$ Potential Energy = 0.02 × 10 × 2

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3 years ago

The weight of an object is the same on two different planets. The mass of planet A is only sixty percent that of planet B. Find

natka813 [3]

Answer:

0.775

Explanation:

The weight of an object on a planet is equal to the gravitational force exerted by the planet on the object:

$F=G\frac{Mm}{R^2}$

where

G is the gravitational constant

M is the mass of the planet

m is the mass of the object

R is the radius of the planet

For planet A, the weight of the object is

$F_A=G\frac{M_Am}{R_A^2}$

For planet B,

$F_B=G\frac{M_Bm}{R_B^2}$

We also know that the weight of the object on the two planets is the same, so

$F_A = F_B$

So we can write

$G\frac{M_Am}{R_A^2} = G\frac{M_Bm}{R_B^2}$

We also know that the mass of planet A is only sixty percent that of planet B, so

$M_A = 0.60 M_B$

Substituting,

$G\frac{0.60 M_Bm}{R_A^2} = G\frac{M_Bm}{R_B^2}$

Now we can elimanate G, MB and m from the equation, and we get

$\frac{0.60}{R_A^2}=\frac{1}{R_B^2}$

So the ratio between the radii of the two planets is

$\frac{R_A}{R_B}=\sqrt{0.60}=0.775$

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