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Kryger [21]
3 years ago
5

When astronauts travel to the moon, their bodies experience a lower gravitational pull than on Earth. Which type of pull are the

y experiencing?
Physics
2 answers:
Georgia [21]3 years ago
5 0

Answer:

The pull the astronauts feel in the moon will be gravitational too.

Explanation:

The pull will be gravitational too because there's a gravitational force exerted by the moon over the astronaut, this force keeps pulling the astronaut towards the moon surface but it's weaker than in earth because the mass of the moon is significantly less that the mass of the earth.

postnew [5]3 years ago
3 0
They are experiencing the pull of leaving the atmosphere

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A sodium has an atomic number of 11 and the atomic mass of 23. Determine the its proton, electrons, and neutrons
ioda

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7 0
3 years ago
PART ONE
stira [4]

Answer:

3.64×10⁸ m

3.34×10⁻³ m/s²

Explanation:

Let's define some variables:

M₁ = mass of the Earth

r₁ = r = distance from the Earth's center

M₂ = mass of the moon

r₂ = d − r = distance from the moon's center

d = distance between the Earth and the moon

When the gravitational fields become equal:

GM₁m / r₁² = GM₂m / r₂²

M₁ / r₁² = M₂ / r₂²

M₁ / r² = M₂ / (d − r)²

M₁ / r² = M₂ / (d² − 2dr + r²)

M₁ (d² − 2dr + r²) = M₂ r²

M₁d² − 2dM₁ r + M₁ r² = M₂ r²

M₁d² − 2dM₁ r + (M₁ − M₂) r² = 0

d² − 2d r + (1 − M₂/M₁) r² = 0

Solving with quadratic formula:

r = [ 2d ± √(4d² − 4 (1 − M₂/M₁) d²) ] / 2 (1 − M₂/M₁)

r = [ 2d ± 2d√(1 − (1 − M₂/M₁)) ] / 2 (1 − M₂/M₁)

r = [ 2d ± 2d√(1 − 1 + M₂/M₁) ] / 2 (1 − M₂/M₁)

r = [ 2d ± 2d√(M₂/M₁) ] / 2 (1 − M₂/M₁)

When we plug in the values, we get:

r = 3.64×10⁸ m

If the moon wasn't there, the acceleration due to Earth's gravity would be:

g = GM / r²

g = (6.672×10⁻¹¹ N m²/kg²) (5.98×10²⁴ kg) / (3.64×10⁸ m)²

g = 3.34×10⁻³ m/s²

4 0
3 years ago
What's the formula to calculate the radius of pendulum bob ​
Svetradugi [14.3K]

Answer:

The combination, L = I / (m * R) , that appears in the equation for the period of a physical pendulum, is called radius of oscillations

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How much time does it take for a bird flying at a speed of 45 miles per hour to travel a distance
Marina CMI [18]

Answer:

40

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