How does the size of a nucleus compare to the amount of space that electrons have to orbit around it
1 answer:
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Answer:
of
is 0.0513
Explanation:
Solubility equilibrium of :
Solubility product of (
) is written as-
Where and
represents equilibrium concentration (in molarity) of
and
respectively.
Molar mass of = 183.48 g/mol
So, solubility of =
= 0.234M
1 mol of gives 1 mol of
and 2 moles of
upon dissociation.
so, = 0.234 M and
=
so,