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Roman55 [17]
3 years ago
7

The element californium (cf) sells for $1000 per µg. assuming 6.02 x 1023 atoms of cf have a mass of 251 grams, how many atoms o

f cf could you buy for 1 u.s. penny?
Chemistry
1 answer:
saveliy_v [14]3 years ago
3 0

Answer:- 2.40*10^1^0atoms

Solution:- It is a simple unit conversion problem. We could solve this using dimensional analysis.

We know that, 1 US dollar = 100 cents

1 cent  = 1 US penny

So, 1 US dollar = 100 US pennies

1g=10^6\mu g

Let's make the set up starting with 1 penny as:

1penny(\frac{$1}{100pennies})(\frac{1\mu g}{$1000})(\frac{1g}{10^6\mu g})(\frac{6.02*10^2^3atoms}{251g})

= 2.40*10^1^0atoms

Therefore, we can bye 2.40*10^1^0atoms of Cf in one US penny.

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Please Help! Let P and V represent the pressure and volume of Xe(g). If a piston is used to reduce the volume of the gas to V/2
Elza [17]

1) 2P

2) Average speed does not change

Explanation:

1)

To solve the first part of the problem, we can use Boyle's Law, which states that:

"For a fixed mass of an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"

Mathematically:

pV=const.

where

p is the pressure of the gas

V is its volume

For the Xe gas in this problem we can write

p_1 V_1 = p_2 V_2

where:

p_1 = P is the initial pressure

V_1=V is the initial volume

V_2=\frac{V}{2} is the final volume

Solving for p2, we find the final pressure:

p_2=\frac{P V_1}{V_2}=\frac{pV}{V/2}=2P

So, the pressure has doubled.

2)

The average speed of the atoms/molecules in the gas is given by the formula

v_{rms}=\sqrt{\frac{3RT}{M}}

where

R is the gas constant

T is the absolute temperature (in Kelvin) of the gas

M is the molar mass of the gas

v_{rms} is known as rms speed of the particles in the gas

From the formula, we see that the speed of the atoms in the gas depends only on the temperature of the gas.

In the Xe(g) gas in this problem, the temperature is kept constant; therefore, since nothing changes in the formula, this means that the average speed also does not change.

8 0
4 years ago
Does riding a bike with larger tires help you go faster even if you pedal at the same rate A:if the person moves faster, then th
Alekssandra [29.7K]

Answer:

Yes, bikes with larger tires help you go faster.

B: if a person rides a bike with larger tires ,then the person with move faster than on a bike with smaller tires

Explanation:

Bikes with larger wheels cover more distances in one revolution, when compared to bikes with a much smaller wheel, if the wheels are turning at the same revolution per minutes. Although more effort is put into turning a big wheel, when compared to that for a smaller wheel, but it will go faster if you can keep it spinning at the same rate as a small one.

8 0
3 years ago
A gas is initially at a pressure of 225 kPa and a temperature of 245 K in a container that is 4.5 L. If the gas is compressed to
Artyom0805 [142]
Use the ideal gas equation PV=nRT. You can compare before and after using P1V1/n1T1=P2V2/n2T2. Since the number of moles remains constant you can disregard moles from the equation and use pressure, volume and temp. Make sure your pressure is converted to atmospheres, your volume is in liters, and your temperature is in kelvins.
6 0
3 years ago
Find the percent composition of each element in KMnO4
VARVARA [1.3K]
The way you want to find the percent composition would be by breaking down the problem like so:

K= atomic mass of K which is 39.098
Mn = atomic mass of Mn which is 54.938
O= atomic mass of o which is 15.999

Then you want to add 39.098+ 54.938+ 15.999 and you get 110.035 which is the molar mass for KMnO

Then you want to take each molar mass and then divide it 110.035 and multiply by 100

Ex. K = 39.098/ 110.035 and the multiply what you get by a 100

You do this for the other elements as well good luck!


6 0
3 years ago
If 27.3% of a sample of silver-112 decays in 1.52 hours, what is the half-life (in hours to 3 decimal places)?
ICE Princess25 [194]

<u>Answer:</u> The half life of the sample of silver-112 is 3.303 hours.

<u>Explanation:</u>

All radioactive decay processes undergoes first order reaction.

To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:

k=\frac{2.303}{t}\log \frac{[A_o]}{[A]}

where,

k = rate constant = ?

t = time taken = 1.52 hrs

[A_o] = Initial concentration of reactant = 100 g

[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g

Putting values in above equation, we get:

k=\frac{2.303}{1.52hrs}\log \frac{100}{72.7}\\\\k= 0.2098hr^{-1}

To calculate the half life period of first order reaction, we use the equation:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life period of first order reaction = ?

k = rate constant = 0.2098hr^{-1}

Putting values in above equation, we get:

t_{1/2}=\frac{0.693}{0.2098hr^{-1}}\\\\t_{1/2}=3.303hrs

Hence, the half life of the sample of silver-112 is 3.303 hours.

6 0
3 years ago
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