Answer:
x=-4 y=-1
Step-by-step explanation:
Let's solve your system by substitution.
−3x−8y=20;y=5x+19
Rewrite equations:
y=5x+19;−3x−8y=20
Step: Solve y=5x+19for y:
y=5x+19
Step: Substitute5x+19foryin−3x−8y=20:
−3x−8y=20
−3x−8(5x+19)=20
−43x−152=20(Simplify both sides of the equation)
−43x−152+152=20+152(Add 152 to both sides)
−43x=172
−43x
−43
=
172
−43
(Divide both sides by -43)
x=−4
Step: Substitute−4forxiny=5x+19:
y=5x+19
y=(5)(−4)+19
y=−1(Simplify both sides of the equation)
Answer:
x=−4 and y=−1
Answer
After the 10 years with accrued interest, there will be roughly $1,552.92 in the account.
Explanation
Using the given equation A = P(1 +r)^t
We are given that our initial start is $500.
P = 500
We are further told that the percentage interest gained is 12%, so we need to convert this into a decimal to be able to work with it.
12% / 100% = 0.12
r = 0.12
t is then our time in years
t = 10
A = 500(1 + 0.12)^10
A = 500(1.12)^10
A = 500(3.1058)
A = 1,552.92
After the 10 years with accrued interest, there will be roughly $1,552.92 in the account.
Answer:
197,8879 N.
Step-by-step explanation:
The magnitude of the horizontal force exerted on the statue can be calculated using trigonometric functions.
The question given says that <em><u>Nancy</u></em> is <em><u>pushing</u></em> the statue with a force of<em><u> 120 N at a 60° angle to the horizontal</u></em> and <em><u>Harry</u></em> is <em><u>pulling</u></em> the statue with a force of <u><em>180 N at a 40° angle with the horizontal</em></u>.
With that information can be calculated the horizontal force exerted on the statue by Nancy, the horizontal force exerted on the statue by Harry and, adding that results, the total horizontal magnitude can be calculated.
The cosine function can be used to calculate the horizontal component of the forces exerted by Nancy and Harry, to determine the horizontal component of the force exerted on the statue.
F= (120 N cos 60°) + (180 N x cos 40°)
F= 197,8879 N
If the sales department wants to place an order for 253,625 third grade math books for a region. How can the sale manager estimate the number of math books to be sure that there are more then enough is: The manager should carryout survey based on the number of people per class and provide 25,362 books.
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How the sale can manager estimate the number of math books </h3>
Since extra math's books will be needed after giving out the available math's books.
Hence:
Additional maths books=10%× 253,625
Additional maths books=25,362 books
Based on the above calculation the manager should carryout survey based on the number of people per class and provide them with 25,362 books.
Therefore how can the sale manager estimate the number of math books to be sure that there are more then enough is that the manager should carryout survey based on the number of people per class and provide 25,362 books.
Learn more about How the sale can manager estimate the number of math books here:brainly.com/question/18558957
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