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slamgirl [31]
3 years ago
5

Which of the following best defines 4 to the power of 2 over 3?. . A. Square root of 16. . B. Cube root of 4. . C. Square root o

f 4. . D. Cube root of 16.
Mathematics
1 answer:
Usimov [2.4K]3 years ago
4 0
x^{m/n}  =  \sqrt[n]{ x^{m} }
4 ^{2/3} =  \sqrt[3]{4 ^{2} }  =  \sqrt[3]{16}
Answer: D ) Cube root of 16
Thank you.
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Which recursive formula can be used to generate the sequence shown, where f(1) = 5 and n > 1?
saveliy_v [14]

You can try them out and see which one works.

a: f(2) = f(1) +6 = 5+6 = 11 . . . . . . not this one

b: f(1) = f(2) -6 = -1-6 = -7 . . . . . . not this one (5 ≠ -7)

c: f(2) = f(1) - 6 = 5 - 6 = -1 . . . . . this gives the right f(2)

d: f(2 = -6(f(1) = -6(5) = -30 . . . . not this one

_____

The appropriate choice is ...

... f(n +1) = f(n) - 6

— — — — — 

You can also recognize that the next term is 6 less than the current one, so f(n+1) = f(n) - 6, which corresponds to the 3rd selection.

7 0
3 years ago
Read 2 more answers
What is 1/10 of 209? Enter your answer in the box as a decimal.
VMariaS [17]

Answer:

20.9

Step-by-step explanation:

8 0
3 years ago
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Maurice buys a dozen of donuts on sale for $7.99 before tax.
adoni [48]

Answer:

$8.30

Step-by-step explanation:

7.99 + 4% = 8.30

5 0
3 years ago
Solve for e.<br> 9e + 4 = -5e + 14 + 13e
Snezhnost [94]

Answer:

17e+18

Step-by-step explanation:

9e+4=-5e+14+13e

4e+4+14+13e

17e+4+14

17e+18

4 0
3 years ago
Read 2 more answers
Derive the equation of the parabola with a focus at (0, −4) and a directrix of y = 4.
CaHeK987 [17]

<u>Answer:</u>

y=-\frac{1}{16} x^2

<u>Step-by-step explanation:</u>

Equation of parabola with focus at (0,-4) and directrix is y=4.

We know that parabola is the locus of all the points such that the distance from fixed point on the parabola to fixed line directrix is the same.

The parabola is opening downwards.

Let any point on parabola is (x,y).

Distance from focus(0,-4) to (x,y) = \sqrt{(x-0)^2+(y-(-4))^2}=|y-4|

\sqrt{(x-0)^2+(y-+4)^2}=|y-4|

(x-0)^2+(y+4)^2=(y-4)^2

(x)^2+(y+4)^2=(y-4)^2

x^2+(y^2+4y+4y+16)=y^2-4y-4y+16

x^2+y^2+8y+16=y^2-8y+16

x^2+16y^2=0

16y=-x^2

y=-\frac{1}{16} x^2

6 0
2 years ago
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