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pickupchik [31]
4 years ago
5

A flat square coil of wire with 15 turns and an area of 0.40 m2 is placed with the plane of its area parallel to a magnetic fiel

d of 0.75 T. The coil is flipped so its plane is perpendicular to the magnetic field in a time of 0.050 s. What is the magnitude of the average induced emf in the coil?
Physics
1 answer:
Dmitry_Shevchenko [17]4 years ago
4 0

Answer:

90 V

Explanation:

Parameters given:

Number of turns, N = 15 turns

Area of coil, A = 0.4 m^2

Magnetic field, B = 0.75 T

Time taken, t = 0.05 s

The average induced EMF in a coil due to the presence of a magnetic field is given as:

V = \frac{-NBA}{t}

V = \frac{-15 * 0.75 * 0.4}{0.05}\\ \\\\V = -90 V

The magnitude of the average induced EMF will be:

|V| = |-90| V = 90 V

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\tau=\dfrac{L_f-L_i}{t}\\\Rightarrow \tau=\frac{0.6-3.8}{1.3}\\\Rightarrow \tau=-2.46\ Nm

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Angular acceleration is given by

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Work done is given by

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The power is -28.29 W

6 0
3 years ago
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