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lys-0071 [83]
2 years ago
11

From what height must an oxygen molecule fall in a vacuum so that its kinetic energy at the bottom equals the average energy of

an oxygen molecule at 300 K ?
Physics
1 answer:
alexandr1967 [171]2 years ago
4 0

Answer:

The  value is  h  = 11930 \ m

Explanation:

From the question we are told that

    The  temperature is  T  =  300 \  K

     

Generally the root mean square speed of the  oxygen molecules is mathematically represented as

        v  =  \sqrt{\frac{3 *  R  *  T }{M} }  =  \sqrt{ 2 *  g  *  h }

Here  R is the gas constant with a value  R  =  8.314 \  J\cdot K^{-1} \cdot \  mol^{-1}

    M  is the molar mass of oxygen molecule with value M  =  0.032 \  kg /mol

So  

     \frac{3 *  8.314   *  300 }{0.032}   =  2 *  9.8  *  h

=>    h  = 11930 \ m

   

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How much wood could a wood chuck chuck if a wood chuck could chuck wood
krek1111 [17]

Answer:

As much wood as a woodchuck could chuck, If a woodchuck could chuck wood.

Explanation:

3 0
2 years ago
A 49.3 g ball of copper has a net charge of 2.0 µc. what fraction of the copper's electrons has been removed? (each copper atom
Serggg [28]
First, find how many copper atoms make up the ball: 
 moles of atoms = (49.3 g) / (63.5 g per mol of atoms) = 0.<span>77638</span><span>mol 
</span> # of atoms = (0.77638 mol) (6.02 × 10^23 atoms per mol) = 4.6738*10^23<span> atoms </span>

<span> There is normally one electron for every proton in copper. This means there are normally 29 electrons per atom:
</span> normal # electrons = (4.6738 × 10^23 atoms) (29 electrons per atom) = <span> <span>1.3554</span></span><span>× 10^25 electrons 
</span>
<span> Currently, the charge in the ball is 2.0 µC, which means -2.0 µC worth of electrons have been removed.
</span><span> # removed electrons = (-2.0 µC) / (1.602 × 10^-13 µC per electron) = 1.2484 × 10^13 electrons removed
 
</span><span> # removed electrons / normal # electrons = </span>
<span>(1.2484 × 10^13 electrons removed) / (1.3554 × 10^25 electrons) = 9.21 × 10^-13 </span>

<span> That's 1 / 9.21 × 10^13 </span>
7 0
3 years ago
Two technicians are discussing electronic leveling systems. Technician A says that a weight should be placed in the vehicle as p
Ronch [10]

Answer:

C. Both A and B

Explanation:

<em>Electronic leveling systems: </em>These are automatic lifting jacks use for raising  wheels and vehicle when parked or when work is to be done on the vehicle engine underneath or on wheels. unlike the manual jacks it is very quick and efficient.

Both technician right, for Technician A, a weight may be use during the procedure for balancing and leveling when raising, and for Technician B, the sensor in the electronic leveling systems is adjustable to adjust the height so as to maintain balancing and levelling.

8 0
2 years ago
When mapping the equipotentials on the plates with different electrode configurations you may find that some have significant ar
Olenka [21]

Answer:

v = 10 V and E = 2 10³ N/C

Explanation:

The electrical potentials and the electric field at one point are related by the expression

            ΔV = - ∫ E. dS

Where the bold indicates vector quantities, E is the electric field and S is the line of displacement of the load, in general displacement is perpendicular to the equipotential lines, which reduces the product scales to the ordinary product.

 If the potential difference is the most usual that is V = 10 V, the electric field is

   s = 0.5 cm = 0.5 10⁻² m

                E = ΔV / S

                E = 10/0.5 10⁻²

                 E = 2 10³ N / C

4 0
3 years ago
An acorn falls 10 meters in 4 seconds. What is its average velocity?
quester [9]

Answer:

Average velocity, V = 2.5m/s

Explanation:

Given the following data

Displacement = 10m

Time = 4secs

Average velocity can be defined as the rate of change in displacement with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, average velocity is given by the equation;

Velocity = \frac{displacement}{time}

V = \frac{d}{t}

Substituting into the above equation;

V = \frac{10}{4}

Average velocity, V = 2.5m/s

3 0
2 years ago
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