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3 years ago

Properties of convex mirror

Physics

1 answer:

Ahat [919]3 years ago

6 0

Answer:

The image result of an object reflected by a convex mirror is typically virtual, upright, and smaller. Discover how moving the object farther away from the mirror's surface affects the size of the virtual image formed behind the mirror

Explanation:

You might be interested in

The Assignment: A fixed quantity of an ideal gas (R 0.28 kJ/kgK; Cv-0.71kJ/kgK) is expanded from an initial condition of 35 bar,

Nikolay [14]

Answer:

Index of expansion: 4.93

Δu = -340.8 kJ/kg

q = 232.2 kJ/kg

Explanation:

The index of expansion is the relationship of pressures:

pi/pf

The ideal gas equation:

p1*v1/T1 = p2*v2/T2

p2 = p1*v1*T2/(T2*v2)

500 C = 773 K

20 C = 293 K

p2 = 35*0.1*773/(293*1.3) = 7.1 bar

The index of expansion then is 35/7.1 = 4.93

The variation of specific internal energy is:

Δu = Cv * Δt

Δu = 0.71 * (20 - 500) = -340.8 kJ/kg

The first law of thermodynamics

q = l + Δu

The work will be the expansion work

l = p2*v2 - p1*v1

35 bar = 3500000 Pa

7.1 bar = 710000 Pa

q = p2*v2 - p1*v1 + Δu

q = 710000*1.3 - 3500000*0.1 - 340800 = 232200 J/kg = 232.2 kJ/kg

7 0

3 years ago

Milk is an example of a(n)<br> solution<br> homogeneous mixture<br> colloid<br> compound

soldier1979 [14.2K]

Answer:

it is C. Colloid

Explanation:

8 0

3 years ago

Which of the following types of electromagnetic radiation has the shortest frequency? (2 points) Infrared waves Microwaves Ultra

Irina18 [472]

In order from shortest to longest frequency, the electromagnetic waves can be ranked :

1. X-rays

2. Ultraviolet

3. Infrared

4. Microwave

X-rays has the shortest frequency which ranges between 30 petahertz to 30 exahertz. X-rays have the smallest wavelengths at 0.01-10 nanometers. Its energy ranges between 100eV to 100keV.

5 0

3 years ago

The Gibson family have bought tickets to the Christmas Market. There are 4 mothers, 2 grand-mothers and 4 daughters. What is the

koban [17]

The minimum number of tickets that could admit all of them is six (6).

This thing is impossible to explain in words, so I shall attempt it with a diagram:

Here are the six ladies:

   ( A ) ( B )
      |    |
      |    |
   ( C ) ( D )
      |       |
    |       |
   ( E ) ( F )

-- 'E' and 'F' are the daughters of 'C' and 'D' .

-- 'C' and 'D' are the daughters of 'A' and 'B' .

So look what we have now:

-- 'A' and 'B' are the mothers of 'C' and 'D' .
   There's 2 of the mothers.

-- 'C' and 'D' are the mothers of 'E' and 'F' .
   There's the OTHER 2 mothers.

-- 'A' and 'B' are the grandmothers of 'E' and 'F' .
    There's the 2 grandmothers.

-- 'E' and 'F' are the daughters of 'C' and 'D' .
   There's 2 of the daughters.

-- 'C' and 'D' are the daughters of 'A' and 'B' .
   There's the OTHER 2 daughters.

You want to know what ? !
The group is even bigger than THAT.
There are also 2 GRAND-daughters in the family ... 'E' and 'F' .

So now you have a list of 12 people ! ... 4 mothers, 2 grandmothers,
4 daughters, and 2 grand-daughters ... and they all get in to the
Christmas Market with only six tickets. Legally !

Such a deal !

Don't forget : Christmas this year is also the first day of Chanukah !
   All for the same price !

5 0

3 years ago

Initially, a 2.00-kg mass is whirling at the end of a string (in a circular path of radius 0.750 m) on a horizontal frictionless

drek231 [11]

Answer:

$v_f = 15 \frac{m}{s}$

Explanation:

We can solve this problem using conservation of angular momentum.

The angular momentum $\vec{L}$ is

$\vec{L} = \vec{r} \times \vec{p}$

where $\vec{r}$ is the position and $\vec{p}$ the linear momentum.

We also know that the torque is

$\vec{\tau} = \frac{d\vec{L}}{dt} = \frac{d}{dt} ( \vec{r} \times \vec{p} )$

$\vec{\tau} = \frac{d}{dt} \vec{r} \times \vec{p} + \vec{r} \times \frac{d}{dt} \vec{p}$

$\vec{\tau} = \vec{v} \times \vec{p} + \vec{r} \times \vec{F}$

but, as the linear momentum is $\vec{p} = m \vec{v}$ this means that is parallel to the velocity, and the first term must equal zero

$\vec{v} \times \vec{p}=0$

$\vec{\tau} = \vec{r} \times \vec{F}$

But, as the only horizontal force is the tension of the string, the force must be parallel to the vector position measured from the vertical rod, so

$\vec{\tau}_{rod} = 0$