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Airida [17]
3 years ago
9

How many terms are in the expression shown below?

Mathematics
1 answer:
stich3 [128]3 years ago
4 0

Answer:

3 terms. All of the numbers are considered terms.

Step-by-step explanation:

If it asked for variables, it would be 2.

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Help please!
Anna71 [15]

Answer:

y= -4x^2 + 15x - 14

Step-by-step explanation:

A parabola is always in the form y = ax^2 + bx + c.

Substitute each point to produce different equations:

-14 = 0a + 0b + c = c

so c = -14

-3 = a1^2 + b1 + c = a + b - 14

so a + b = 11

0 = a2^2 + b2 + c = 4a + 2b -14 = 0

so 4a + 2b = 14

if we double a + b = 11 we get 2a + 2b = 22

Subtract this from 4a + 2b = 14 and we get 2a = -8 so a= -4 and b = 11 - a = 15

We don't need to use the (3,5) points as we have all the information we need.

4 0
2 years ago
Read 2 more answers
The value pi/2 is a solution for the equation 2sin^2 x -sinx-1=0
nikklg [1K]

me so sorry come back laterAnswer:

Step-by-step explanation:me so sorry come back later

7 0
2 years ago
Suppose that y varies inversely with x. Use the information to find k, and then choose the equation of variation. x = 2 when y =
Sergeeva-Olga [200]

Answer:

y = \frac{22}{x}

Step-by-step explanation:

given that y varies inversely with x then the equation relating them is

y = \frac{k}{x} ← k is the constant of variation

To find k use the condition x = 2 when y = 11

k = yx = 11 × 2 = 22

y = \frac{22}{x} ← equation of variation

4 0
3 years ago
Read 2 more answers
Which only lists multiples of 16? O1,2,4, 8, 16 O 16, 24, 32, 40 O16, 32, 48, 64 O 1,2, 4, 8, 12, 16​
schepotkina [342]

Answer:

48 & 68

Step-by-step explanation:

if you multiply the numbers you will see that you get 48 & 68 multiple times

5 0
3 years ago
Solve by setting up a system of linear equations with 2 variables and 2 unknowns. Two hundred seventy six students enrolled in a
jeyben [28]

Let us say ,

x=number of students who passed

y=number of students who failed

total number of students =276

x+y=276..................(1)

We are given 5 times the number of students passed as failed.

x=5y.............(2)

plugging value of x from (2) in (1),

5y+y=276

6y=276

y=46

x=5y=46*5=230

x=number of students who passed=230

4 0
3 years ago
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