Answer:
Uh i think its a uhhh carrot
Step-by-step explanation:
To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Answer:
As x ⇒-∞, P(x) ⇒ -∞
As x ⇒ ∞, P(x) ⇒ ∞
Step-by-step explanation:
To find left hand end behavior, plug in negative infinity into the function and evaluate...
P(x) = 3(-∞) = -3(∞) = -∞
The 'y' values of the function decrease towards negative infinity as the 'x' values approach negative infinity
P(x) = 3(∞) = ∞
The 'y' values of the function increase towards positive infinity as the 'x' values approach positive infinity
Answer A because of the absolute value sign.
