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3 years ago

Indicate the number corresponding to each coefficient required to write the balanced equation for the reaction:

2 answers:

5 0

The number of corresponding to each coefficient required to write the balanced equation for the reaction is as below

2 HNO3 + Mg(OH)2 = 2H2O + Mg(NO3)2
the coefficient is therefore
a=2
b=1
c=2
d=1

2 moles of HNO3 reacted with 1 mole of Mg(OH)2 to form 2 moles of H2O and 1 mole of Mg(NO3)2

Alla [95]3 years ago

4 0

Answer:

a 2

b 1

c 2

d 1

Explanation:

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Which statement describes the general trends in electronegativity and metallic properties as the elements in Period 2 are consid

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Answer:

Electronegativity increases and metallic

properties decrease.

Explanation:

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3 years ago

During surgery, a patient receives 3.5 pt of plasma. How many milliliters of plasma were given?

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Answer:

1656.116

Explanation:

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3 years ago

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C.Pennsylvania Titusville is in the state of Pennsylvania

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3 years ago

Read 2 more answers

Which reactions are oxidation-reduction reactions? check all that apply. fes(s) 2hcl(aq) â†’ h2s(g) fecl2(g) agno3(aq) nacl(aq)

Dafna1 [17]

oxidation-reduction reactions are -

2C3H6(g) + 9O2(g) → 6CO2(g) + 6H2O(g)
Fe2O3(s) + 3CO(g) → 2Fe(l) + 3CO2(g)

For reaction,

2C3H6(g) + 9O2(g) → 6CO2(g) + 6H2O(g)

On reactant side:

Oxidation state of Carbon = +2

Oxidation state of Oxygen = 0

On product side:

Oxidation state of Carbon = +4

Oxidation state of Oxygen = -2

Here, carbon's oxidation state is rising from +2 to +4. As a result, it is oxidizing and the oxygen's oxidation state is decreasing from 0 to -2. As a result, it is decreasing.

For reaction,

Fe2O3(s) + 3CO(g) → 2Fe(l) + 3CO2(g)

When reacting:

Iron's oxidation state is +3.

Carbon's oxidation state is +2.

On product side:

Iron's oxidation state is zero.

Carbon's oxidation state is +4.

Here, carbon's oxidation state is rising from +2 to +4. As a result, it is being oxidized and the iron's oxidation state is changing from +3 to 0. As a result, it is decreasing.

To learn more about oxidation-reduction from given link

brainly.com/question/5794822

#SPJ4

7 0

1 year ago

An isotope of cesium-137 has a half-life of 30 years. If 5.0g of cesium-137 decays over 60 years. How many grams will remain.

LenKa [72]

Answer:

1.25 gram of cesium-137 will remain.

Explanation:

Given data:

Half life of cesium-137 = 30 year

Mass of cesium-137 = 5.0 g

Mass remain after 60 years = ?

Solution:

Number of half lives passed = Time elapsed / half life

Number of half lives passed = 60 year / 30 year

Number of half lives passed = 2

At time zero = 5.0 g

At first half life = 5.0 g/2 = 2.5 g

At 2nd half life = 2.5 g/ 2 = 1.25 g

Thus. 1.25 gram of cesium-137 will remain.

6 0

3 years ago