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3 years ago

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In the summer of 1859, Edwin Drake became the first person to strike oil in the United States while drilling in Titusville,_____

.
A. Alaska
B. California
C. Pennsylvania
D. Texas

2 answers:

Nata [24]3 years ago

7 0

C.Pennsylvania Titusville is in the state of Pennsylvania

UNO [17]3 years ago

5 0

C. Titusville Pennsylvania

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What type of cryptography uses two keys instead of just one, generating both a private and a public key?

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Answer:

It is known as asymmetric key cryptography it is also called public key cryptography.

Explanation:

Asymmetric key cryptography method makes use of two keys.One is used for encryption and the second one for decryption. The public key serves to encrypt plain text or verify a digital signature, while the private key is used to decrypt or decipher the encrypted text or to create a digital signature.

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2 years ago

How many sodium atoms does 2NaOH have?

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Answer:

1

Explanation:

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3 years ago

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It is known that the kinetics of recrystallization for some alloy obey the Avrami equation andthat the value of n in the exponen

Paul [167]

Answer:

rate of recrystallization = 4.99 × 10⁻³ min⁻¹

Explanation:

For Avrami equation:

$y = 1-e ^{(-kt^n)} \\ \\ e^{(-kt^n)} = 1-y\\ \\ -kt^n = In(1-y) \\ \\ k = \dfrac{-In(1-y)}{t^n}$

To calculate the value of k which is a dependent variable for the above equation ; we have:

$k = \dfrac{-In(1-0.40)}{200^{2.5}}$

$k = 9.030 \times 10 ^{-7}$

The time needed for 50% transformation can be determined as follows:

$y = 1-e ^{(-kt^n)} \\ \\ e^{(-kt^n)} = 1-y\\ \\ -kt^n = In(1-y) \\ \\ t =[ \dfrac{-In(1-y)}{k}]^{^{1/n}}$

$t_{0.5} =[ \dfrac{-In(1-0.4)}{9.030 \times 10^{-7}}]^{^{1/2.5}}$

= 200.00183 min

The rate of reaction for Avrami equation is:

$rate = \dfrac{1}{t_{0.5}}$

$rate = \dfrac{1}{200.00183}$

rate = 0.00499 / min

rate of recrystallization = 4.99 × 10⁻³ min⁻¹

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2 years ago

What is the first step in creating a unit conversion factor?

NNADVOKAT [17]

Determining the units.

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2 years ago

Radio waves travel at the speed of light which is 3.00 x 10^8. How many minutes does it take for a radio message to reach saturn

ryzh [129]

Answer:

43.89 min

Explanation:

Given that:-

The speed of light = $3.00\times 10^8\ m/s$

The distance = $7.9\times 10^8\ km$

The conversion of distance in km to distance into m is shown below as:-

1 km = 1000 m

So,

Distance = $7.9\times 10^8\times 1000\ m=7.9\times 10^{11}\ m$

The relation between speed distance and time is shown below as:-

$Speed=\frac{Distance}{Time}$

Thus,

$3.00\times 10^8=\frac{7.9\times 10^{11}}{Time}$

$300000000\times time=10^{11}\times \:7.9\ s$

Time = 2633.33 seconds

Also, 1 s = 1/60 min

So,

Time= $\frac{2633.33}{60}\ min=43.89\ min$

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2 years ago