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saw5 [17]
2 years ago
12

An isotope of cesium-137 has a half-life of 30 years. If 5.0g of cesium-137 decays over 60 years. How many grams will remain.

Chemistry
1 answer:
LenKa [72]2 years ago
6 0

Answer:

1.25 gram of cesium-137 will remain.

Explanation:

Given data:

Half life of cesium-137 = 30 year

Mass of cesium-137 = 5.0 g

Mass remain after 60 years = ?

Solution:

Number of half lives passed = Time elapsed / half life

Number of half lives passed = 60 year / 30 year

Number of half lives passed = 2

At time zero = 5.0 g

At first half life = 5.0 g/2 = 2.5 g

At 2nd half life = 2.5 g/ 2 = 1.25 g

Thus. 1.25 gram of cesium-137 will remain.

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The order of reaction with respect to B is, zero order reaction.

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Explanation :

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Expression for rate law for first observation:

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Expression for rate law for second observation:

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Expression for rate law for third observation:

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Dividing 1 from 2, we get:

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The order of reaction with respect to A is, first order reaction.

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