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anzhelika [568]
2 years ago
10

Ethane (C2H6) is one of many compounds that burns in oxygen to form carbon dioxide and water, as represented by the equation bel

ow. Which substance is a product in this reaction? *
Chemistry
1 answer:
Ulleksa [173]2 years ago
5 0

Answer: From the question, the equation which is 2C2H6 + 7O2 --> 4CO2 + 6H2O has the products as 4CO2 + 6H2O( which is carbon dioxide and water)

Explanation:

Chemical reaction is a process in chemistry which leads to the formation of new substances referred to as PRODUCTS from combination of two or more substances called REACTANTS. There are different types of chemical reaction which includes COMBUSTION REACTION that is mostly seen in hydrocarbons.

Ethane is an example of a saturated hydrocarbon ( that is all the four bonds of carbon are single bonds) which undergoes combustion reaction with oxygen molecule. Ethane will burn in air( oxygen) to give off carbon dioxide and water as products of the chemical reaction.

2C2H6 + 7O2 --> 4CO2 + 6H2O

Shane and oxygen is the reactants of the chemical reaction while carbon dioxide and water is the products.

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Since the action and reaction are exactly equal and oppositely directed , how can there be a net force on an object ?
erma4kov [3.2K]

Answer: Net force is the summation of all the forces involved or acting on an object.

Explanation: For action and reaction situation it states that the Fa = -Fb. Both forces with equal magnitudes but opposite direction will cancel out each other having a zero net force.

6 0
3 years ago
A compound is found to contain 43.66% of P and 56.33% of O.
jek_recluse [69]

Answer: P2O5 is the empirical formula.

Explanation: When given percentages you can assume that many grams of each atom are in the compound. Then you divide grams by the molar mass of each element, giving you moles. Once you have moles, divide by the smaller molar amount, which should give you 1 mol of Phosphorus and 2.5 mol of Oxygen. Then multiply by 2 in order for both moles to be a whole number. This gets you 2 and 5.

6 0
2 years ago
What are some signs of cyanide poisoning visible on a corpse?
lina2011 [118]
Hello!
I saw this question and instantly knew I could help. I recently took a course on toxic gasses and poisons. Here's what I know.

It can be swallowed, inhaled, or absorbed through skin. It is generally released from its host compound by acids, such as the hydrochloric acid found in the stomach. The poison in the seeds is released only if the seeds are chewed.

Effects and symptoms:
Cyanide prevents the red blood cells from absorbing oxygen. It's called chemical asphyxia.
Smelling of a toxic dose of the gas can cause immediate unconsciousness, convulsions and death within one to fifteen minutes.
If swallowed a fatal dose can take up to twenty minutes or longer, esp. if swallowed on a full stomach.
If a near-lethal dose is absorbed through the skin, inhaled or swallowed the symptoms will include gasping for breath, dizziness, flushing, headache, nausea, vomiting, rapid pulse, and a drop in blood pressure causing fainting.
<span>With a lethal dose, convulsions with in four hours, except in the case of sodium nitroprusside, when death can be delayed as long as 12 hours after ingestion. </span>The victims blood may appear purple or cherry red, as in carbon monoxide poisoning, and the corpse may have pinker than normal skin.
<span>the famous bitter almond odor can be a clue and maybe noticeable at autopsy, but not everyone is capable of smelling it.

Hope this helped! :)</span>
5 0
3 years ago
Suppose that a certain biologically important reaction is quite slow at physiological temperature (37 oC) in the absence of a ca
Oksi-84 [34.3K]

Answer:

30 kJ

Explanation:

Arrhenius equation is given by:

k=Aexp(-Ea/RT)\\

Here, k is rate constant, A is Pre-exponential factor, Ea is activation energy and T is temperature.

taking natural log of both side

ln k = ln A - Ea/RT

In Arrhenius equation, A, R and T are constant.

Therefore,

ln\frac{k_2}{k_1} =\frac{Ea_1-Ea_2}{RT}

Ea_1-Ea_2 is the  lowering in activation energy by enzyme,

R = 8.314 J/mol.K

T = 37°C + 273.15 = 310 K

\frac{k_2}{k_1} =1\times 10^5

ln 1\times 10^5 =\frac{Ea_1-Ea_2}{RT}\\{Ea_1-Ea_2} = 11.512 \times 8.314 \times 310\\=29670\ J\\=30\ kJ

4 0
3 years ago
Why do you turn a C-terminal aminoacid's carboxyl group into an ester before reducing it to an alcohol? Why not just use LiAlH4
Troyanec [42]

Answer:

Esters are both inorganic and organic acids .... Regarding the second question, it is believed that it is carried out in this way in order to recognize the C-terminal amino acid in a peptide within a protein

Explanation:

The explanation of this question is according to what was interpreted in the question, since it is considered that it is poorly written ...

What happens in this chemical reaction is that it first becomes an ester (organic or inorganic acid) so that it is later recognized in the complex peptide structure.

4 0
3 years ago
Read 2 more answers
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