Answer:
Molecular formula = C₂H₆
Explanation:
Given data:
Percentage of hydrogen = 20.0 %
Percentage of carbon = 80.0 %
Molar mass = 30.0 g
Empirical formula = ?
Solution:
Number of gram atoms of H = 20 / 1.01 = 19.8
Number of gram atoms of C = 80 /12 = 6.7
Atomic ratio:
C : H
6.7/6.7 : 19.8/6.7
1 : 3
C : H = 1 : 3
Empirical formula is CH₃.
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula = CH₃ = 12×1 +3×1.01 = 15.03 g/mol
n = 30 g/mol / 15.03 g/mol
n = 2
Molecular formula = n (empirical formula)
Molecular formula = 2 (CH₃)
Molecular formula = C₂H₆
<span>To find the balanced molecular equation, we need to find the symbols for each element and their charges and then balanced the equation. This comes out to:
Al(OH)3(aq) + 3HBR(aq) ---> AlBr3(aq) + 3H2O(l)
The net ionic equation is adding the charges and separating them into basic components.
Al3+ + 3OH- + 3H+ + 3BR- --> Al3+ + 3Br + H3O+
We can cancel out the aluminum and bromine to get:
3OH-(aq) + 3H+(aq) --> 3H2O(l)</span>
Answer:
To find the number of neutrons in an isotope, subtract the number of protons from the atomic mass of the isotope. The atomic number of the element equals the number of protons.
Answer: 154.09 g
Explanation:
3 Mg + 2 FeCl3 = 3 MgCl2 + 2 Fe
The mass of MgCl2 produced is calculated:
m MgCl2 = 175 g FeCl3 * (1 mol FeCl3 / 162.2 g) * (3 mol MgCl2 / 2 mol FeCl3) * (95.21 g MgCl2 / 1 mol) = 154.09 g
The question is incomplete. The complete question is :
C. Balance these fossil-fuel combustion reactions. (1 point)
C8H18(g) + 12.5O2(g) → ____CO2(g) + 9H2O(g) + heat
CH4(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
C3H8(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
C6H6(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
Solution :
C8H18(g) + 12.5O2(g) → __8__CO2(g) + 9H2O(g) + heat
When 1 part of octane reacts with 12.5 parts of oxygen, it gives 8 parts of carbon dioxide and 9 parts of water along with liberation of energy.
CH4(g) + __2__O2(g) → __1__CO2(g) + __2__H2O(g) + heat
When 1 part of methane reacts with 2 parts of oxygen, it gives 1 part of carbon dioxide and 2 parts of water along with liberation of energy.
C3H8(g) + __5__O2(g) → __3__CO2(g) + __4__H2O(g) + heat
When 1 part of propane reacts with 5 parts of oxygen, it gives 3 part of carbon dioxide and 4 parts of water along with liberation of energy.
C6H6(g) + __1/2__O2(g) → __6__CO2(g) + __3__H2O(g) + heat
When 1 part of propane reacts with 1/2 parts of oxygen, it gives 6 part of carbon dioxide and 3 parts of water along with liberation of energy.
