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anzhelika [568]
2 years ago
10

Ethane (C2H6) is one of many compounds that burns in oxygen to form carbon dioxide and water, as represented by the equation bel

ow. Which substance is a product in this reaction? *
Chemistry
1 answer:
Ulleksa [173]2 years ago
5 0

Answer: From the question, the equation which is 2C2H6 + 7O2 --> 4CO2 + 6H2O has the products as 4CO2 + 6H2O( which is carbon dioxide and water)

Explanation:

Chemical reaction is a process in chemistry which leads to the formation of new substances referred to as PRODUCTS from combination of two or more substances called REACTANTS. There are different types of chemical reaction which includes COMBUSTION REACTION that is mostly seen in hydrocarbons.

Ethane is an example of a saturated hydrocarbon ( that is all the four bonds of carbon are single bonds) which undergoes combustion reaction with oxygen molecule. Ethane will burn in air( oxygen) to give off carbon dioxide and water as products of the chemical reaction.

2C2H6 + 7O2 --> 4CO2 + 6H2O

Shane and oxygen is the reactants of the chemical reaction while carbon dioxide and water is the products.

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A 100.0-mL sample of 1.00 M NaOH is mixed with 50.0 mL of 1.00 M H2SO4 in a large Styrofoam coffee cup calorimeter fitted with a
worty [1.4K]

Answer:

THE ENTHALPY CHANGE IN KJ/MOLE IS +114 KJ/MOLE.

Explanation:

Heat = mass * specific heat capacity * temperature rise

Total volume = 100 + 50 = 150 mL

Total mass = density * volume

Total mass = 1 * 150 mL = 150 g

So therefore, the heat evolved during the reaction is:

Heat = 150 * 4.18 * ( 31.4 - 22.3)

Heat = 150 * 4.18 * 9.1

Heat = 5705.7 J

Equation for the reaction:

2 NaOH(aq) + H2SO4(aq) → Na2SO4(aq) + 2 H2O(l)  

From the equation, 2 moles of NaOH reacts with 1 mole of H2SO4 to produce 1 mole of Na2SO4 and 2 moles of water

50 mL of 1 M of H2SO4 contains

50 * 1 / 1000 mole of acid

= 0.05 mole of acid

The production of 1 mole of water evolved 5705.7 J of heat and hence the enthalpy changein kJ per mole will be:

0.05 mole of H2SO4 produces 5705.7 J of heat

1 mole of H2SO4 will produce 5705.7 / 0.05 J

= 114,114 J / mole

In kj/mole = 114 kJ/mole.

Hence, the enthalpy change of the reaction in kJ /mole is +114 kJ/mole.

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