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Pani-rosa [81]
3 years ago
15

Jan and Wayne went to the store to buy some groceries. Jan bought 2 cans of corn beef hash and 3 cans of creamed chipped beef fo

r $4.95. Wayne bought 3 cans of corn beef hash and 2 cans of creamed chipped beef for $5.45. Let H represent the price of a can of corn beef hash, and C represent the price of a can of creamed chipped beef. solve for H and C
Mathematics
2 answers:
olasank [31]3 years ago
7 0
You can solve this by using the system of equations.
Jan - 4.95 = 2H + 3C
Wayne - 5.45 = 3H + 2C

Use elimination.
-3(2H + 3C = 4.95)
2(3H + 2C = 5.45)

Solve. And you'll get:
-6H + (-9C) = -14.85
6H + 4C = 10.9

Cross out -6H and 6H because they cancel out. And you're left with:
-9C = -14.85
4C = 10.9

Add -9C with 4C, and -14.85 with 10.9.
-5C = -3.95

Divide each side with -5.
C = $0.79

Now to figure out what H is, just substitute the C in one of the equations with 0.79.
5.45 = 3H + 2(0.79)
5.45 = 3H + 1.58
-1.58            -1.58
3.87 = 3H
3.87/3 = 3/3(H)
1.29 = H

Finished!
bija089 [108]3 years ago
5 0

Answer:

H = the unit price of corn beef hash

C = the unit price of creamed chipped beef

Step-by-step explanation:

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