If I remember correctly, the solutions are only on the solid line or in the shaded area? therefore Answers could be:
6.) (-3,0.5) (-4,0) (-2,0) (-2,-5) (-3,-5) (-4,-1) (-3,-1) (-2,-1)
7.) (-1,0) (-2,0) (-3,0) (0,-1) (-4,-1)
Answer:
x1 = 2 -
x2= 2 +
Step-by-step explanation:
x/4 + 6 = 7 + 1/4x
(x^2 - 1)/4x = 1
x^2 - 1 = 4x
x^2 - 4x -1 = 0
x= (4+
)/2 = 2 -
x= 2 +
Answer:
1. y = -x + 3
2. y = x - 3
3. y = 3x + 1
4. y = -3x - 3
Step-by-step explanation:
Hello! sorry, I just saw your message on the question I answered before asking for help so here you go, these are the answers, hope this helps.
Pls mark me brainliest if you can:)
For any arbitrary 2x2 matrices

and

, only one choice of

exists to satisfy

, which is the identity matrix.
There is no other matrix that would work unless we place some more restrictions on

. One such restriction would be to ensure that

is not singular, or its determinant is non-zero. Then this matrix has an inverse, and taking

we'd get equality.
n, n + 1, n + 2, n + 3 - four consecutive integers
-142 - the sum
The equation:
n + (n + 1) + (n + 2) + (n + 3) = -142
n + n + 1 + n + 2 + n + 3 = -142
4n + 6 = -142 |subtract 6 from both sides
4n = -148 |divide both sides by 4
n = -37
n + 1 = -37 + 1 = -36
n + 2 = -37 + 2 = -35
n + 3 = -37 + 3 = -34
Answer: -37, -36, -35, -34.