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mario62 [17]
3 years ago
12

What is the simplified form of 24 y to the fifth power over 15 x to the eighth power divided by 8 y squared over 4 x to the four

th power?
Mathematics
2 answers:
aleksley [76]3 years ago
8 0
12 y cubed over 15 x to the sixth power
egoroff_w [7]3 years ago
7 0

Answer:

\dfrac{4y^3}{5x^4}

Step-by-step explanation:

We are given,

The expression is \dfrac{\dfrac{24y^5}{15x^8}}{\dfrac{8y^2}{4x^4}}.

Upon simplifying, we get,

\dfrac{\dfrac{24y^5}{15x^8}}{\dfrac{8y^2}{4x^4}}\\\\\\\dfrac{24y^5\times 4x^4}{15x^8\times 8y^2}}\\\\\\\dfrac{3y^3\times 4}{15x^4}}\\\\\\\dfrac{4y^3}{5x^4}}

Thus, we have,

The simplified form of the given expression is \dfrac{4y^3}{5x^4}.

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Someone please help i dont know how to solve for 6 and 7 <br> :(
Sphinxa [80]

If I remember correctly, the solutions are only on the solid line or in the shaded area? therefore Answers could be:

6.) (-3,0.5) (-4,0) (-2,0) (-2,-5) (-3,-5) (-4,-1) (-3,-1) (-2,-1)

7.) (-1,0) (-2,0) (-3,0) (0,-1) (-4,-1)

7 0
3 years ago
2(x/8 + 3) = 7 + 1/4x what is x
malfutka [58]

Answer:

x1 = 2 -\sqrt{5}

x2= 2 +\sqrt{5}

Step-by-step explanation:

x/4 + 6 = 7 + 1/4x

(x^2 - 1)/4x = 1

x^2 - 1 = 4x

x^2 - 4x -1 = 0

x= (4+\sqrt{20})/2 = 2 -\sqrt{5}

x= 2 +\sqrt{5}

5 0
3 years ago
Pls help me, its not hard
natulia [17]

Answer:

1. y = -x + 3

2. y = x - 3

3. y = 3x + 1

4. y = -3x - 3

Step-by-step explanation:

Hello! sorry, I just saw your message on the question I answered before asking for help so here you go, these are the answers, hope this helps.

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3 0
3 years ago
Can you think of any 2x2 matrices d for which cd = dc for all 2x2 matrices c? give 2 different examples of such matricesd.
Ksju [112]
For any arbitrary 2x2 matrices \mathbf C and \mathbf D, only one choice of \mathbf D exists to satisfy \mathbf{CD}=\mathbf{DC}, which is the identity matrix.

There is no other matrix that would work unless we place some more restrictions on \mathbf C. One such restriction would be to ensure that \mathbf C is not singular, or its determinant is non-zero. Then this matrix has an inverse, and taking \mathbf D=\mathbf C^{-1} we'd get equality.
6 0
3 years ago
Find four consecutive integers with the sum of -142
Akimi4 [234]

n, n + 1, n + 2, n + 3 - four consecutive integers

-142 - the sum

The equation:

n + (n + 1) + (n + 2) + (n + 3) = -142

n + n + 1 + n + 2 + n + 3 = -142

4n + 6 = -142     |subtract 6 from both sides

4n = -148    |divide both sides by 4

n = -37

n + 1 = -37 + 1 = -36

n + 2 = -37 + 2 = -35

n + 3 = -37 + 3 = -34

Answer: -37, -36, -35, -34.

5 0
3 years ago
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