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3 years ago

10

If you have 5 packages of brushes and 32 single brushes and each package has the same number of brushes. In all, he has 123 brus

hes for his students to use. How many brushes are in each packag?

2 answers:

Salsk061 [2.6K]3 years ago

8 0

We would start with this:

123-32 = 91 because of the amount of single brushes

Then we have 91 non-single brushes that are in the packages, and if there are 5 packages, then next we must divide.

91÷5 ≈18 packages with 32 single brushes

Katyanochek1 [597]3 years ago

6 0

5x+32=123
5x=91
x= 91/5 brushes

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The relationship between the percentage of frozen citrus crop, and the cost of box of oranges is an illustration of a linear function.

<em>The linear equation of the function is: </em> $g(P) = 22.9P+7$ <em>.</em>
<em>The inverse function is: </em> $g^{-1}(c) = \frac{1}{22.9}(c - 7)$ <em> .</em>
<em>A practical domain is from 0% to 100%</em>
<em>A practical range is from 7 to 29.9 </em>

<u>A. Input quantity</u>

The input quantity is the percentage of frozen citrus crop

<u />

<u>B. Output quantity </u>

The output quantity is the cost of box of oranges

<u>C. The linear function</u>

We have:

$(P_1,c_1) = (20\%,11.58)\\(P_2,c_2) = (80\%,25.32)$

<em>Calculate the slope of the function</em>

$m = \frac{c_2 - c_1}{P_2 - P_1}$

$m = \frac{25.32 - 11.58}{80\%-20\%}$

$m = \frac{13.74}{60\%}$

$m = 22.9$

<em>The linear equation is calculated as follows:</em>

$c -c_1 = m(P-P_1)$

$c -11.58= 22.9(P-20\%)$

$c-11.58 = 22.9P-4.58$

<u>D. Rewrite as y = mx + b</u>

We have:

$c-11.58 = 22.9P-4.58$

Collect like terms

$c = 22.9P - 4.58 + 11.58$

$c = 22.9P+7$

<em>The function is:</em>

$g(P) = 22.9P+7$

<u>E. A practical domain</u>

The domain is the possible values of P. Because P is a percentage, its possible values are 0% to 100%.

The domain of the function is: $[0\%,100\%]$

<u>F. A practical range</u>

When P = 0%

$c = 22.9 \times 0\% + 7 = 7$

When P = 100%

$c = 22.9 \times 100\% + 7 = 29.9$

Hence, the range of the function is: $[7,29.9]$

G. The meaning of $g^{-1}(12)$

The inverse function of g(P) is $g^{-1}(P)$

So:

$g^{-1}(12)$ is the percentage of frozen citrus crop, when the cost is $12.

<u>H. The inverse formula</u>

We have:

$c = 22.9P+7$

Subtract 7 from both sides

$c - 7 = 22.9P$

Make P the subject

$P = \frac{1}{22.9}(c - 7)$

So, the inverse formula is:

$g^{-1}(c) = \frac{1}{22.9}(c - 7)$

Substitute 12 for c

$g^{-1}(12) = \frac{1}{22.9}(12 - 7)$

$g^{-1}(12) = \frac{1}{22.9} \times 5$

$g^{-1}(12) = 22\%$

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