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vodomira [7]
2 years ago
9

The number of I atoms in the reactants is greater than the number in the product : True or False

Chemistry
1 answer:
Sphinxa [80]2 years ago
8 0

Explanation:

We can summarize the reaction shown as:

                2F₂  +   I₂  →   2F₃I

Since I is purple

         F is the green

The number of I atoms in the reactants is greater than the number in the product

False:

The number of I atoms on both side of the expression is 2

There are 4 atoms of F in both the reactants and the products.

False:

There are 4 atoms of F on the reactant side and 6 atoms of F on the product side

The illustration represents a valid chemical transformation. True or false

False

The reaction does not represent a valid chemical transformation because in a valid chemical transformation, the number of atoms on both sides of the expression must be the same.

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The arrangement of the solutions based on their absorption from highest frequency to lowest frequency :

b.NaNO_{2} > c.H_{2} O > a.NaCl

<h3>What is absorption frequency?</h3>
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  • In a way, an emission spectrum is the opposite of an absorption spectrum.
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Please help, with step by step work
natali 33 [55]

\qquad ☀️\pink{\bf{ {Answer  = \: \:   85.57g }}}

Molar mass of \bf Cu_2O

\qquad \twoheadrightarrow\sf 63.546 \times 2 +16

\qquad \pink{\twoheadrightarrow\bf 143.092 g}

<u>As we know</u>–

1 mol =\bf 6.02×10^{23} formula units

1 mol\bf Cu_2O = 143.092 g = \bf 6.02×10^{23}formula units

Henceforth –

\bf 3.60×10^{23} formula units \bf Cu_2O–

\qquad \sf :\implies \dfrac{143.092 \times3.60×10^{23  }}{6.02×10^{23}}

\qquad \sf :\implies \dfrac{143.092 \times3.60×\cancel{10^{23  }}}{6.02×\cancel{10^{23}}}

\qquad \pink{:\implies\bf 85.57 g}

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