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horrorfan [7]
3 years ago
13

What are the respective concentrations (m) of mg2 and c2h3o2- afforded by dissolving 0.600 mol mg(c2h3o2)2 in water and diluting

to 135 ml?
Chemistry
1 answer:
SOVA2 [1]3 years ago
8 0
<span>1 mol mag acetate dissociates into 1 mol Mg ion and 2 mols acetate ions in water. Therefore, if 0.6 mol mg of acetate is dissolved in 0.135 literss of water, we will have 0.6/0.135 = 4.44 moles / lit Mg2+ ions and 0.6*2/0.135 = 8.88 moles / liter C2H3O2- ions.</span>
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Ppredict the identity of the precipitate in the below reaction:<br><br> BaCl2(aq) + K2SO4(aq) →
Annette [7]

Answer:  The precipitate formed is BaSO_4

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid or precipitated form are represented by (s) after their chemical formulas.  

A double displacement reaction in which one of the product is formed as a solid is called as precipitation reaction.  

The balanced chemical equation is:

K_2SO_4(aq)+BaCl_2(aq)\rightarrow BaSO_4(s)+2KCl(aq)

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Fill in the blanks and balance with the correct coefficient​
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\huge\mathrm{  \underline{Answer}}࿐

The Balanced equation will be :

\mathrm{ \boxed2Fe +  \boxed3Cl_2  \rightarrow  \boxed2FeCl_3}

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How many grams of oxygen are required to react with 13.0 grams of octane (C8H18) in the combustion of octane in gasoline?
egoroff_w [7]

Grams of oxygen are required to react with 13.0 grams of octane (C8H18) in the combustion of octane in gasoline is 45.5g

Octane is a hydrocarbon which burns in gasoline in presence of oxygen according to the given balanced chemical equation,

2C₈H₁₈ + 25O₂------> 16CO₂ + 18H₂0

Molar mass of octane = 114.23g/mol

Molar mass of Oxygen = 32g/mol

According to the stiochiometry of the balanced equation the mole ratio of Octane and Oxygen is 2:25

2 mole of octane needs 25 mole of oxygen

1 mole of octane needs 12.5 moleof oxygen

114.23g of octane needs 400g of oxygen

13g   of octane  needs 45.5g of oxygen

Mass of oxygen needed =45.5g

Hence, the Mass of oxygen needed is 45.5g for the combustion of octane in gasoline.

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