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alisha [4.7K]
1 year ago
14

At what temperature does sulfur tetrafluoride have a density of 0.230 g/L at 0.0721 atm?

Chemistry
1 answer:
Allisa [31]1 year ago
8 0

Explanation:

At 365 K temperature sulfur tetrafluoride have a density of 0.260 g/L at 0.0721 atm.

What is an ideal gas equation?

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide

the given mass by the number of moles to get molar mass.

Given data:

P= 0.0721 atm

n=\frac{mass}{molar \;mass}n=

molarmass

mass

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}R=0.082057338LatmK

−1

mol

−1

T=?

Putting value in the given equation:

\frac{PV}{RT}=n

RT

PV

=n

density = \frac{2 \;atm\; X molar\; mass}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}density=

0.082057338LatmK

−1

mol

−1

XT

2atmXmolarmass

0.260 g/L = \frac{0.0721 \;atm\; X 108.07 g/mol}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}0.260g/L=

0.082057338LatmK

−1

mol

−1

XT

0.0721atmX108.07g/mol

T = 365.2158727 K= 365 K

Hence , at 365 K temperature sulfur tetrafluoride have a density of 0.260 g/L at 0.0721 atm.

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Answer:

a. 74.55 g/mol.

b. 91.70 g.

c. 8.40%.

d. 1.23 mol/L.

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∵ Formula weight of KCl = atomic weight of K + atomic weight of Cl

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∴ Formula weight of KCl = atomic weight of K + atomic weight of Cl = 39.098 g/mol + 35.45 g/mol = 74.548 g/mol ≅ 74.55 g/mol.

<em>b. Calculate the mass of KCl in grams.</em>

  • we can use the relation:

<em>no. of moles (n) = mass/molar mass.</em>

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<em>c. Calculate the percent by mass of KCl in this solution.</em>

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mass of KCl = 91.70 g,

mass of the solution = 1000.0 g of water + 91.70 g of KCl = 1091.70 g.

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<em>d. Calculate the molarity of the solution.</em>

Molarity is the no. of moles of solute per 1.0 L of the solution.

<em>M = (no. of moles of KCl)/(Volume of the solution (L))</em>

no. of moles of KCl = 1.23 mol,

Volume of the solution = mass of water / density of water = (1000.0 g)/(1.00 g/mL) = 1000.0 mL = 1.0 L.

M = (1.23 mol)/(1.0 L) = 1.23 mol/L.

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