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alisha [4.7K]
1 year ago
14

At what temperature does sulfur tetrafluoride have a density of 0.230 g/L at 0.0721 atm?

Chemistry
1 answer:
Allisa [31]1 year ago
8 0

Explanation:

At 365 K temperature sulfur tetrafluoride have a density of 0.260 g/L at 0.0721 atm.

What is an ideal gas equation?

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide

the given mass by the number of moles to get molar mass.

Given data:

P= 0.0721 atm

n=\frac{mass}{molar \;mass}n=

molarmass

mass

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}R=0.082057338LatmK

−1

mol

−1

T=?

Putting value in the given equation:

\frac{PV}{RT}=n

RT

PV

=n

density = \frac{2 \;atm\; X molar\; mass}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}density=

0.082057338LatmK

−1

mol

−1

XT

2atmXmolarmass

0.260 g/L = \frac{0.0721 \;atm\; X 108.07 g/mol}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}0.260g/L=

0.082057338LatmK

−1

mol

−1

XT

0.0721atmX108.07g/mol

T = 365.2158727 K= 365 K

Hence , at 365 K temperature sulfur tetrafluoride have a density of 0.260 g/L at 0.0721 atm.

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Answer:

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Explanation:

You must start by stating the chemical equation for the reaction of ammonia, carbon dioxide, and methane to produce aminoaceto nitrile.

1. Word equation:

Ammonia + Carbon dioxide + Methane → Aminoacetonitrile + Water

2. Balanced chemical equation:

       8NH_3+5CO_2+3CH_4\rightarrow 4C_2H_4N_2 +10H_2O

3. Convert the mass of each reactant into number of moles:

<u>Formula:</u>

  • Number of moles = mass in grams/molar mass

<u>2.11g NH₃</u>

  • Number of moles = 2.11g / 17.03g/mol = 0.124 mol NH₃

<u>14.9g CO₂</u>

  • Number of moles = 14.9g/44.01g/mol = 0.339 mol CO₂

<u>1.75g CH₄</u>

  • Number of moles = 1.75g/16.04g/mol = 0.109 mol CH₄

4. Theoretical mol ratio

From the balanced chemical equation, using the coefficientes:

         8molNH_3:5molCO_2:3molCH_4:4molC_2H_4N_2:10molH_2O

5. Limiting reagent

The available amounts of the reactants are:

  • 0.124 mol NH₃
  • 0.339 mol CO₂
  • 0.109 mol CH₄

Fom the theoretical mole ration, to react with 0.124 mol of NH₃ you would need:

  • 0.124molNH₃ × (5molCO₂/8molNH₃) = 0.0775 mol CO₂

Since there are 0.339 moles available, this is in excess.

  • 0.124molNH₃ × (3molCH₄/8molNH₃) =  0.0465mol CO₂

Since there are 0.109 moles available, this is in excess too.

Hence, the limiting reagent is NH₃.

6. Yield

Use the theoretical ratio:

  • 0.124molNH₃ × (4molC₂H₄N₂ / 8molNH₃) = 0.0620 mol C₂H₄N₂

Convert to grams:

  • Mass = number of moles × molar mass
  • 0..0620 mol × 56.068g/mol = 3.48 g of C₂H₄N₂ ← answer

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4 years ago
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Answer:

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A geochemist in the field takes a 25.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X .
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Answer:

1- Yes, we can calculate the solubility of mineral compound X.

2- 0.012 g/mL.

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The volume of water sample = 25.0 mL.

Weight of the mineral compound X after evaporation, drying, and washing = 0.30 g.

∴ Yes, we can calculate the solubility of mineral compound X.

<u><em>2-  If you said yes, calculate it.</em></u>

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∴ 1.0 mL  of water sample contains → ??? g of the mineral compound X.

1.0 ml of water sample will contain (0.3 g/25.0 mL) 0.012 g.

<em>∴ The solubility of the mineral compound X in the water sample is</em> <u><em>0.012 g/mL.</em></u>

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The atomic orbital, can be considered as the electron wave function of an atom.

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