1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Aliun [14]
3 years ago
12

Light of wavelength λ1 illuminates a double slit, and interference fringes are observed on a screen behind the slits. When the w

avelength is changed to λ2, the fringes get closer together. Is λ2 larger or smaller than λ1?
Physics
1 answer:
alex41 [277]3 years ago
3 0

Answer:

λ2 < λ1

Explanation:

- Young's experiment of interference of light when passed through a slit has determined a result. We will use an expression derived from the results that relates wavelength and and the spread of the interference pattern using:

                                            sin (Q) = n*lambda / d

Where,

n is the order of fringe about the central order

lambda is the wavelength of light

d is the space between grating

Q is the angle between the two successive interference fringe

- So in our case using a light of wavelength lambda 2 the pattern got closer together or we could say that angle Q got smaller. According to the relationship given we can see as angle Q decreases when lambda decreases. So we can conclude that  λ2 < λ1.

You might be interested in
A thermometer is placed directly sunlight will it read the temperature of the air or of the sun or of something else??
Norma-Jean [14]
It will read the temperature of the atmosphere.It is unable to read the temperature of the sun because some of the heat energy from the sun is absorbed by the layer of air molecules on Earth.
7 0
4 years ago
Do the math for 30%÷75
Dafna1 [17]

" 30% " means " 0.30 "

30% ÷ 75  means  (0.30 / 75) = <em>0.004</em>

3 0
3 years ago
A car is traveling at 104 km/h when the driver sees an accident 50 m ahead and slams on the brakes. What minimum constant decele
Solnce55 [7]

Answer:

–8.35 m/s²

Explanation:

We'll begin by converting 104 km/h to m/s. This can be obtained as follow:

3.6 Km/h = 1 m/s

Therefore,

104 km/h = 104 km/h × 1 m/s / 3.6 Km/h

104 km/h = 28.89 m/s

Thus, 104 km/h is equivalent to 28.89 m/s.

Finally, we shall determine the deceleration of the car. This can be obtained as follow:

Initial velocity (u) = 28.89 m/s

Final velocity (v) = 0 m/s

Distance (s) = 50 m

Deceleration (a) =?

v² = u² + 2as

0² = 28.89² + (2 × a × 50)

0 = 834.6321 + 100a

Collect like terms

0 – 834.6321 = 100a

–834.6321 = 100a

Divide both side by 100

a = –834.6321 / 100

a = –8.35 m/s²

Thus, the deceleration of the car is –8.35 m/s².

5 0
3 years ago
HURRY ! THE BEST I WILL GIVE THE BRAINLIEST​
erik [133]

The speed of both cars is the same ... 80 km per hour.

But their velocities are different, because DIRECTION is part of velocity, and their directions are different.

6 0
3 years ago
A car of mass 1,000 kilograms is moving initially at the speed of 22 meters/second. When the brakes are applied, it takes the ca
Mariulka [41]

i believe it is C....tell me if im right please<3

4 0
3 years ago
Read 3 more answers
Other questions:
  • What are the SI units for specific heat capacity? <br> A. J <br> B. J/ºC <br> C. J/gºC<br> D. J/g
    5·1 answer
  • Balloon A is negatively not positively charged, and balloon C is negatively not positively charged. If balloon A approaches ball
    15·1 answer
  • How do protons ever fuse together in the presence of the electromagnetic force? There is another force involved here called the
    9·1 answer
  • Calculate the frequency of the 3rd normal mode of a guitar string of length 40.0cm and mass 0.5g when stretched with a tension o
    11·1 answer
  • What was george washingtons favorite game?
    12·1 answer
  • A person lifts a heavy load to a vertical height of 2.0 m in 3 seconds. If he/she had done this more slowly in 6 seconds, the
    14·1 answer
  • Wilbur ran 1-kilometer. Then he ran 500 meters. How many meters did Wilbur run all together?
    10·1 answer
  • 6. Which formula could you use according to the scenario? Five grams of substance occupy 3 cm3 of a flask. Om = du OD Ot= d​
    8·1 answer
  • The specific heat of a substance is 0.215 J/g°C. How much energy is required to raise the temperature of 20 g of the substance f
    10·1 answer
  • A A load of 1000 N can be lifted by applying
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!