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yawa3891 [41]
3 years ago
11

Do the math for 30%÷75

Physics
1 answer:
Dafna1 [17]3 years ago
3 0

" 30% " means " 0.30 "

30% ÷ 75  means  (0.30 / 75) = <em>0.004</em>

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True or false: objects fall toward earth at a rate of 9.8 m/s because of centripetal force.
Citrus2011 [14]
Sadly, no. The statement kind of has some appropriate words in it, but it's badly corrupted. Objects don't fall to Earth at a rate of 9.8 m/s, and the force that accelerates them downward is not a centripetal one.
4 0
3 years ago
A projectile is launched from the ground at an angle of 60o above the horizontal. At what point in its trajectory does it have t
Elodia [21]

Answer:

It's constant everywhere in its trajectory.

Explanation:

the projectile was launched with an initial velocity, the only acceleration that is affecting the projectile's velocity is gravity.

The acceleration of gravity is practically equal everywhere on earth, so during its trajectory, we have to take into consideration only the acceleration because of gravity.

This is only correct because the projectile was launched with an initial velocity and it's not accelerating from rest and then falls.

5 0
3 years ago
A motorcycle moving at 18 m/s decelerates at a rate of 3.6 m/s². What is the car's
Gekata [30.6K]

Answer:

V = 3.6 m/s

Explanation:

Given:

V₀ = 18 m/s

a = - 3,6 m/s²  (The motorcycle is slowing down!)

t = 4 s

____________

V - ?

Motorcycle speed:

V = V₀ + a·t

V = 18 + (-3.6)·4 = 3.6 m/s

5 0
1 year ago
Distance between bholu and golu house house 9 km . bholu has to attend golu birthday party at 7am . he started from his home at
navik [9.2K]
For the rest 3 km


Bholu need to run in 5 minutes so


He need to 3 × 1000 / 5 × 60 m/s

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So , his speed should be 1 m/s to reach in 5 minute



mark as brainliest 5 star
6 0
4 years ago
Read 2 more answers
A voltaic cell is constructed with two Zn2+-Zn electrodes, where the half-reaction is Zn2+ + 2e− → Zn (s) E° = -0.763 V The conc
wariber [46]

Answer : The cell emf for this cell is 0.077 V

Solution :

The balanced cell reaction will be,  

Oxidation half reaction (anode):  Zn(s)\rightarrow Zn^{2+}+2e^-

Reduction half reaction (cathode):  Zn^{2+}+2e^-\rightarrow Zn(s)

In this case, the cathode and anode both are same. So, E^o_{cell} is equal to zero.

Now we have to calculate the cell emf.

Using Nernest equation :

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}{diluted}}{[Zn^{2+}{concentrated}]}

where,

n = number of electrons in oxidation-reduction reaction = 2

E_{cell} = ?

[Zn^{2+}{diluted}] = 0.0111 M

[Zn^{2+}{concentrated}] = 4.50 M

Now put all the given values in the above equation, we get:

E_{cell}=0-\frac{0.0592}{2}\log \frac{0.0111M}{4.50M}

E_{cell}=0.077V

Therefore, the cell emf for this cell is 0.077 V

7 0
4 years ago
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