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Ilia_Sergeevich [38]
3 years ago
10

A car of mass 1,000 kilograms is moving initially at the speed of 22 meters/second. When the brakes are applied, it takes the ca

r 3.0 seconds to stop. What is the force required to stop the car?
A. 2.2 × 104 newtons
B. 2.5 × 103 newtons
C. 7.3 × 103 newtons
D. 1.4 × 103 newtons
Physics
3 answers:
Mariulka [41]3 years ago
4 0

i believe it is C....tell me if im right please<3

boyakko [2]3 years ago
4 0

Answer:

Force, F=7.3\times 10^3\ N

Explanation:

Given that,

Mass of the car, m = 1000 kg

Initial speed of the car, u = 22 m/s

Finally, the brakes are applied, v = 0

Time, t = 3 s

We need to find the force required to stop the car. It is given by using second law of motion as :

F=m\times a

F=\dfrac{m(v-u)}{t}

F=\dfrac{1000(22)}{3}

F = 7333.33 N

or

F=7.3\times 10^3\ N

So, the force required to stop the car is 7.3\times 10^3\ N. Hence, this is the required solution.

himiko2 years ago
0 0

yes it is c

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3 years ago
A heat pump is to be used for heating a house in winter. The house is to be maintained at 70°F at all times. When the temperatur
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Answer:

\dot{W_{H} } = 4244.48 Btu/h

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Heat is extracted at 40°F i.e T_{L} = 40^{0}F  = 40 + 460 = 500 R

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COP = \frac{T_{H} }{T_{H} - T_{L}  } \\COP = \frac{530 }{530 - 500  }\\ COP = \frac{530}{30} \\COP = 17.67

The minimum power required to run the heat pump is given by the formula:

\dot{W_{H} } = \frac{\dot{Q_{H} }}{COP} \\...............(*)

Where the heat losses from the house, \dot{Q_{H} } = 75,000 Btu/h

Substituting these values into * above

\dot{W_{H} } = \frac{75000}{17.67} \\ \dot{W_{H} } = 4244.48 Btu/h

3 0
3 years ago
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5.38 m/s^2

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NET force causing the object to accelerate  =  50 -10 = 40 N

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6 0
1 year ago
A nonzero net force acts on a particle and does work. Which one of the following statements is true?
arlik [135]

Answer:

option (D) is correct.

Explanation:

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