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Ilia_Sergeevich [38]
3 years ago
10

A car of mass 1,000 kilograms is moving initially at the speed of 22 meters/second. When the brakes are applied, it takes the ca

r 3.0 seconds to stop. What is the force required to stop the car?
A. 2.2 × 104 newtons
B. 2.5 × 103 newtons
C. 7.3 × 103 newtons
D. 1.4 × 103 newtons
Physics
3 answers:
Mariulka [41]3 years ago
4 0

i believe it is C....tell me if im right please<3

boyakko [2]3 years ago
4 0

Answer:

Force, F=7.3\times 10^3\ N

Explanation:

Given that,

Mass of the car, m = 1000 kg

Initial speed of the car, u = 22 m/s

Finally, the brakes are applied, v = 0

Time, t = 3 s

We need to find the force required to stop the car. It is given by using second law of motion as :

F=m\times a

F=\dfrac{m(v-u)}{t}

F=\dfrac{1000(22)}{3}

F = 7333.33 N

or

F=7.3\times 10^3\ N

So, the force required to stop the car is 7.3\times 10^3\ N. Hence, this is the required solution.

himiko3 years ago
0 0

yes it is c

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Why if you charge a mate by an amount of time you are not doing work?

This happens because work is defined as the displacement done by a force:

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An angle has a value of 2.2 radians. Find its value in degrees.
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Answer:

The value of 2.2 radians in degree is 126.11°.

Explanation:

Given that,

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We need to calculate the value in degrees

We know that,

1\ radians = \dfrac{180}{\pi}

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2.2\ radians = 126.11^{\circ}

Hence, The value of 2.2 radians in degree is 126.11°.

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3 years ago
Which group was guaranteed voting rights by the Fifteenth Amendment?
castortr0y [4]

Explanation:

The 15th Amendment to the U.S. Constitution granted African American men the right to vote by declaring that the "right of citizens of the United States to vote shall not be denied or abridged by the United States or by any state on account of race, color, or previous condition of servitude." Although ratified on February 3, 1870, the promise of the 15th Amendment would not be fully realized for almost a century. Through the use of poll taxes, literacy tests and other means, Southern states were able to effectively disenfranchise African Americans. It would take the passage of the Voting Rights Act of 1965 before the majority of African Americans in the South were registered to vote.

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a disk with a radius of 0.1 m is spinning about its center with a constant angular speed of 10 rad/sec. What are the speed and m
padilas [110]

The speed of the bug at the rim of the circular disk is \boxed{1\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}} and the acceleration of the bug is \boxed{10\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {{{\text{s}}^{\text{2}}}}}} \right.\kern-\nulldelimiterspace} {{{\text{s}}^{\text{2}}}}}}.

Further Explanation:

Given:

The angular velocity of the disk is 10\,{{{\text{rad}}} \mathord{\left/{\vphantom {{{\text{rad}}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}.

The radius of the circular disk is 0.1\,{\text{m}}.

Concept:

The linear speed of the bug present at the rim of the circular disk is given by.

v = r \times \omega  

Here, v is the linear speed,r is the radius of the disk and \omega is the angular speed of the disk.

Substitute 0.1\,{\text{m}} for r and 10\,{{{\text{rad}}} \mathord{\left/{\vphantom {{{\text{rad}}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}} for \omega in above expression.

\begin{aligned}v &= 0.1\,{\text{m}} \times 10\,{{{\text{rad}}} \mathord{\left/{\vphantom {{{\text{rad}}} {\text{s}}}} \right. \kern-\nulldelimiterspace} {\text{s}}} \\&= 1\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}} \\\end{aligned}  

The magnitude of the centripetal acceleration of the bug cling to the rim of the disk is given as.

{a_c} = \dfrac{{{v^2}}}{r}  

Substitute 1\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}} for v and 0.1\,{\text{m}} for r in above equation.

\begin{aligned}a_c&=\dfrac{(1\text{m/s})^2}{0.1\text{m}}\\&=\frac{1}{0.1}\text{m/s}^2\\&=10\,\text{m/s}^2\end{aligned}  

Thus, the speed of the bug at the rim of the circular disk is \boxed{1\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}} and the acceleration of the bug is \boxed{10\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {{{\text{s}}^{\text{2}}}}}} \right.\kern-\nulldelimiterspace} {{{\text{s}}^{\text{2}}}}}}.

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Answer Details:

Grade: College

Chapter: Uniform Circular motion

Subject: Physics

Keywords:  Circular disk, circular motion, angular speed, linear speed, bug clinging, rim of the disk, acceleration, magnitude, constant, rad/s.

7 0
3 years ago
Read 2 more answers
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