Answer:
a) see attached, a = g sin θ
b)
c) v = √(2gL (1-cos θ))
Explanation:
In the attached we can see the forces on the sphere, which are the attention of the bar that is perpendicular to the movement and the weight of the sphere that is vertical at all times. To solve this problem, a reference system is created with one axis parallel to the bar and the other perpendicular to the rod, the weight of decomposing in this reference system and the linear acceleration is given by
Wₓ = m a
W sin θ = m a
a = g sin θ
b) The diagram is the same, the only thing that changes is the angle that is less
θ' = 9/2 θ
c) At this point the weight and the force of the bar are in the same line of action, so that at linear acceleration it is zero, even when the pendulum has velocity v, so it follows its path.
The easiest way to find linear speed is to use conservation of energy
Highest point
Em₀ = mg h = mg L (1-cos tea)
Lowest point
Emf = K = ½ m v²
Em₀ = Emf
g L (1-cos θ) = v² / 2
v = √(2gL (1-cos θ))
The force applied by the man is 60 N
Explanation:
We can solve this problem by applying Newton's second law, which states that:
(1)
where
is the net force acting on the child+cart
m is the mass of the child+cart system
a is their acceleration
In this problem, we have:
m = 30.0 kg is the mass
And there are two forces acting on the child+cart system:
- The forward force of pushing, F
- The force resisting the cart motion, R = 15.0 N
Therefore we can write the net force as
where R is negative since its direction is opposite to the motion
So eq.(1) can be rewritten as
And solving for F,
Learn more about Newton's second law:
brainly.com/question/3820012
#LearnwithBrainly
Answer:
It doesn’t really relate
Explanation:
heavier load the parachute must be moving faster to match the downward force of the greater load
and approx terminal velocity when the parachute is open
velocity for Ping pong ball with parachute = 9m/s
velocity for Soccer ball with parachute = 15m/s
velocity for Golf ball with parachute =24m/s
velocity for Watermelon with parachute = 25m/s
so weight of an object doesn’t really realted how fast it falls with a parachute
