20 POINTS<br> Please answer the question in the photo

Zhao Xue wants to buy milk and yogurt. She wants to buy a total of at least 6.5 gallons of dairy products (condition A), and she

Marta_Voda [28]

Answer: The answer is (D). Zhao Xue doesn’t have enough money left to buy any yofurt

Step-by-step explanation: Given that Zhao Xue is buying buy milk and yogurt, a total of at least 6.5 gallons of dairy products and she has a budget of $20. The given graph represents the constraints on the number of gallons of milk 'M' and yogurt 'Y' Zhao Xue buys. Zhao Xue buys 4 gallons of milk. We need to calculate the number of gallons of yogurt she can buy to meet both her constraints.

From the graph, we can write

Condition A :

$M+Y\geq 6.5.$

Condition B :

$8M+5Y\leq40.$

Now, if she buys 4 gallons of milk, the the conditions become

$4+Y\geq 6.5~~\Rightarrow Y\geq 2.5,\\\\8\times 4+5Y\leq 40~~\Rightarrow Y\leq 1.6.$

Here, there will be no solution to these constraints.

Therefore, she does not have enough money left to buy any yogurt.

Thus, the correct option is (D).

3 0

3 years ago

Can someone help me out with this my grade are bad

Tju [1.3M]

Answer:

2 2/5

Step-by-step explanation:

5 0

2 years ago

You have been doing research for your statistics class on the prevalence of severe binge drinking among teens. You have decided

Serggg [28]

Answer:

(1.218 ; 1.322)

the confidence interval is appropriate

Step-by-step explanation:

The confidence interval :

Mean ± margin of error

Sample mean = 1.27

Sample standard deviation, s = 0.80

Sample size, n = 914

Since we are using tbe sample standard deviation, we use the T table ;

Margin of Error = Tcritical * s/√n

Tcritical at 95% ; df = 914 - 1 = 913

Tcritical(0.05, 913) = 1.96

Margin of Error = 1.96 * 0.80/√914 = 0.05186

Mean ± margin of error

1.27 ± 0.05186

Lower boundary = 1.27 - 0.05186 = 1.218

Upper boundary = 1.27 + 0.05186 = 1.322

(1.218 ; 1.322)

According to the central limit theorem, sample means will approach a normal distribution as the sample size increases. Hence, the confidence interval is valid, the sample size of 914 gave a critical value at 0.05 which is only marginally different from that will obtained using a normal distribution table. Hence, the confidence interval is appropriate

8 0

3 years ago

I need help with my algebra fraction assignments. I need help with page 2, 3,4,5 and 7. I also have additional albebra fraction

PolarNik [594]

Answer:

Step-by-step explanation:

#2 the answer is B, -16/9

do 1/4-5/2

to do this, find the least common denominator. it's 4

1/4-10/4=-9/4

then divide 4 by -9/4. This is the same as 4*-4/9. That is -16/9

#3 the answer is A 9x/x-8

first factor the denominator of the first fraction using special products

x^2-6x-16=(x-8)(x+2)

if you look at the first fraction, you can simplify x+2 leaving you with the fraction 1/x+8

multiply that by 9x, and you get 9x/x-8

#4 the answer is C (2x+1)/2x^2

first add x/4 and 1/8

find the least common denominator. its 8

2x/8 + 1/8 is equal to (2x+1)/8

then multiply that by x^2/4 because dividing a fraction is the same as multiplying its reciprocal

you get (2x+1)/2x^2

#5 the answer is C (x-8)/(x+3)

using special products you can factor the numerator

x^2-4x-32 is the same as (x-8)(x+4)

then, using special products you can also factor the denominator

x^2+7x+12 is the same as (x+4)(x+3)

you can see that both the numerator and the denominator is multiplied by (x+4) you can simplify that. That leaves you with (x-8)/(x+3)

#7 the answer is D 3m

in the numerator in the second fraction, you can factor out 5m^2

leaving you with 5m^2(m-6)/5m^2. simplify the 5m^2 and the m-6

after you simplify both of those, you will get 3m

7 0

4 years ago

57 over 9 solve fraction as it was a division problem

shutvik [7]

The answer is 6.3...

the three repeats

hope this helps!

5 0

3 years ago

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20 POINTS Please answer the question in the photo