The Coners are on a road trip. They

Two ways to write a algebraic expression of n-5

deff fn [24]

-5 + n is another way to write the expression.

5 0

3 years ago

Suppose that bugs are present in 1% of all computer programs. A computer de-bugging program detects an actual bug with probabili

lawyer [7]

Answer:

(i) The probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

Step-by-step explanation:

Denote the events as follows:

B = bugs are present in a computer program.

D = a de-bugging program detects the bug.

The information provided is:

$P(B) =0.01\\P(D|B)=0.99\\P(D|B^{c})=0.02$

(i)

The probability that there is a bug in the program given that the de-bugging program has detected the bug is, P (B | D).

The Bayes' theorem states that the conditional probability of an event E given that another event X has already occurred is:

$P(E|X)=\frac{P(X|E)P(E)}{P(X|E)P(E)+P(X|E^{c})P(E^{c})}$

Use the Bayes' theorem to compute the value of P (B | D) as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D|B)P(B)+P(D|B^{c})P(B^{c})}=\frac{(0.99\times 0.01)}{(0.99\times 0.01)+(0.02\times (1-0.01))}=0.3333$

Thus, the probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii)

The probability that a bug is actually present given that the de-bugging program claims that bug is present is:

P (B|D) = 0.3333

Now it is provided that two tests are performed on the program A.

Both the test are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is:

P (Bugs are actually present | Detects on both test) = P (B|D) × P (B|D)

$=0.3333\times 0.3333\\=0.11108889\\\approx 0.1111$

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii)

Now it is provided that three tests are performed on the program A.

All the three tests are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is:

P (Bugs are actually present | Detects on all 3 test)

= P (B|D) × P (B|D) × P (B|D)

$=0.3333\times 0.3333\times 0.3333\\=0.037025927037\\\approx 0.037$

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

4 0

3 years ago

22. 38.56 + 8 + 99.41 = 86.68

Andru [333]

0.1

44

43

4

3432

27

87

34

23.9

05

345

234.70

6 0

3 years ago

Venus and Serena measured a tennis court and found that it was 42ft longer than it was wide and had a perimeter of 228ft. What w

mr_godi [17]

Answer:

length = 78 feet

width = 36 feet

Step-by-step explanation:

Using one variable and an expression, you can set up an equation equal to the perimeter to find the measure of each side:

width = 'w'

length = '42ft longer than it was wide' = w + 42

The general formula for the perimeter of a rectangle:

P = 2w + 2l

Plugging in the given values and variables:

228 = 2w + 2(w + 42)

Distribute: 228 = 2w + 2w + 84

Combine like terms: 144 = 4w

Divide and solve: 36 = w

w = 36 ft

l = 36 + 42 = 78 ft

8 0

3 years ago

If sin just answer the please lol i don't feel like typing ASAP

yaroslaw [1]

Considering that the sine is negative and that the cosine is positive, the angle is on the fourth quadrant, hence option C is correct.

<h3>What are the signs of the sine and of the cosine in each quadrant?</h3>

Quadrant 1: Both positive.

Quadrant 2: Sine positive, cosine negative.

Quadrant 3: Both negative.

Quadrant 4: Sine negative, cosine positive.

Hence, since the sine is negative and that the cosine is positive, the angle is on the fourth quadrant, hence option C is correct.

More can be learned about quadrants at brainly.com/question/28021191

#SPJ1

5 0

1 year ago