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zavuch27 [327]
3 years ago
15

Write the equation of the line that has the indicated slope and contains the indicated point. express the final equation in stan

dard form. m = 9, (−3, 6)
Mathematics
1 answer:
myrzilka [38]3 years ago
6 0
Y-y1=m(x-x1)
y-6=9(x+3)
y-6=9x+27
9x-y=-6-27
9x-y=-33
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What is the correct method of solving the equation x/3-6=9 for x?
AveGali [126]

Answer: The value of x is 45

Step-by-step explanation:

The equation x/3-6=9 is a linear equation, where x/3 is the same as one-third of x.

Thus it is easily simplified as such:

x/3-6=9

Collect like terms

x/3 = 9 + 6

x/3 = 15

i.e (1/3) of X = 15

To get the value of x, cross multiply

x = 3 x 15

x = 45

Thus, the value of x is 45

6 0
3 years ago
3/4 + 1/2 write answer in mixed number in simplest form
Leni [432]
Explaintion

3/4 + 1/2 = 3/4 + 2/4 = 5/4 = 1 1/4
Answer:

1 1/4

Hope this helps
8 0
3 years ago
Find two power series solutions of the given differential equation about the ordinary point x = 0. compare the series solutions
monitta
I don't know what method is referred to in "section 4.3", but I'll suppose it's reduction of order and use that to find the exact solution. Take z=y', so that z'=y'' and we're left with the ODE linear in z:

y''-y'=0\implies z'-z=0\implies z=C_1e^x\implies y=C_1e^x+C_2

Now suppose y has a power series expansion

y=\displaystyle\sum_{n\ge0}a_nx^n
\implies y'=\displaystyle\sum_{n\ge1}na_nx^{n-1}
\implies y''=\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}

Then the ODE can be written as

\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge1}na_nx^{n-1}=0

\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge2}(n-1)a_{n-1}x^{n-2}=0

\displaystyle\sum_{n\ge2}\bigg[n(n-1)a_n-(n-1)a_{n-1}\bigg]x^{n-2}=0

All the coefficients of the series vanish, and setting x=0 in the power series forms for y and y' tell us that y(0)=a_0 and y'(0)=a_1, so we get the recurrence

\begin{cases}a_0=a_0\\\\a_1=a_1\\\\a_n=\dfrac{a_{n-1}}n&\text{for }n\ge2\end{cases}

We can solve explicitly for a_n quite easily:

a_n=\dfrac{a_{n-1}}n\implies a_{n-1}=\dfrac{a_{n-2}}{n-1}\implies a_n=\dfrac{a_{n-2}}{n(n-1)}

and so on. Continuing in this way we end up with

a_n=\dfrac{a_1}{n!}

so that the solution to the ODE is

y(x)=\displaystyle\sum_{n\ge0}\dfrac{a_1}{n!}x^n=a_1+a_1x+\dfrac{a_1}2x^2+\cdots=a_1e^x

We also require the solution to satisfy y(0)=a_0, which we can do easily by adding and subtracting a constant as needed:

y(x)=a_0-a_1+a_1+\displaystyle\sum_{n\ge1}\dfrac{a_1}{n!}x^n=\underbrace{a_0-a_1}_{C_2}+\underbrace{a_1}_{C_1}\displaystyle\sum_{n\ge0}\frac{x^n}{n!}
4 0
3 years ago
Rename the number 780000 = 78
AfilCa [17]
<span>We need to rename the given number which is 780 000 into 78 ________.
=> But before we rename it, we need to find the value of 78
=> Since this is a 6 digit whole number, we have ones, tens, hundreds, thousands, ten thousands, hundred thousands.
=> 7 = hundred thousands
=> 8 = ten thousands
=> 7 hundred thousands + 8 ten thousands
=> Thus, the renamed of 780 000 is 7 hundred 8 ten thousands.

</span>



3 0
4 years ago
4 A figure is graphed on a coordinate grid as shown.
Andrei [34K]

Answer:

i have no idea

Step-by-step explanation:

5 0
3 years ago
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