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Tju [1.3M]
3 years ago
13

a triangle with area 28 square inches has a height that is twi less than four times the base. find the base and the height if th

e tringle?
Mathematics
1 answer:
FromTheMoon [43]3 years ago
4 0

Answer:

b = 4 inches and h = 14 inches

Step-by-step explanation:

Given that,

The area of a triangle, A = 28 sq inches

Height is twice less than 4 times the base.

H = 4b-2, b is base

We know that,

The area of a triangle is given by :

A=\dfrac{1}{2}bh\\\\28=\dfrac{1}{2}\times b\times (4b-2)\\\\56=4b^2-2b\\\\28=2b^2-b\\\\b=4\ inches,-3.5\ inches

Base = 4 inches

Height = 4(4)-2

= 14 inches

Hence, this is the required solution.

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Answer:

(2) The motorcycle cost $12,000 when purchased.

Step-by-step explanation:

In the standard exponential equation, y = ab^x, a is the original value.

Since the equation is V(t) = 12,000(0.75)^t, a is 12,000.

This means that the original value was 12,000.

So, the motorcycle cost $12,000 when it was first purchased.

The correct answer is (2) The motorcycle cost $12,000 when purchased.

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What is the percent of change from 0.36 to 1.19?
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Step-by-step explanation:

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There is a 70 percent chance that an airline passenger will check bags. In the next 16 passengers that check in for their flight
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Answer:

a) P(X=16)=(16C16)(0.7)^{16} (1-0.7)^{16-16}=0.00332

b) P(X

And we can find the individual probabilities like this:

P(X=10)=(16C10)(0.7)^{10} (1-0.7)^{16-10}=0.1649

P(X=11)=(16C11)(0.7)^{11} (1-0.7)^{16-11}=0.2099

P(X=12)=(16C12)(0.7)^{12} (1-0.7)^{16-12}=0.2040

P(X=13)=(16C13)(0.7)^{13} (1-0.7)^{16-13}=0.1465

P(X=14)=(16C14)(0.7)^{14} (1-0.7)^{16-14}=0.0732

P(X=15)=(16C15)(0.7)^{15} (1-0.7)^{16-15}=0.0228

P(X=16)=(16C16)(0.7)^{16} (1-0.7)^{16-16}=0.0033

And replacing we got:

P(X

c) P(x \geq 10) = P(X=10)+P(X=11)+P(X=12)+P(X=13)+P(X=14)+P(X=15)+P(X=16)

And replacing we got 0.825

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=17, p=0.7)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

And we want to find this probability:

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Part b fewer than 10 will check bags

We want this probability:

P(X

We can use the complement rule and we have:

P(X

And we can find the individual probabilities like this:

P(X=10)=(16C10)(0.7)^{10} (1-0.7)^{16-10}=0.1649

P(X=11)=(16C11)(0.7)^{11} (1-0.7)^{16-11}=0.2099

P(X=12)=(16C12)(0.7)^{12} (1-0.7)^{16-12}=0.2040

P(X=13)=(16C13)(0.7)^{13} (1-0.7)^{16-13}=0.1465

P(X=14)=(16C14)(0.7)^{14} (1-0.7)^{16-14}=0.0732

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And replacing we got:

P(X

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We can find this probability like this:

P(x \geq 10) = P(X=10)+P(X=11)+P(X=12)+P(X=13)+P(X=14)+P(X=15)+P(X=16)

And replacing we got 0.825

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