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finlep [7]
3 years ago
7

Suppose that on a routine trip around the galaxy, your dog puts his head out of the spacecraft window (as dogs often do). The so

lar wind has a temperature of approximately 104 K. Would your dog’s head burn up immediately? Explain briefly in the context of temperature versus heat (assume your dog holds his breath during the exercise and can withstand low pressure).
Physics
1 answer:
neonofarm [45]3 years ago
7 0

Answer: Yes, the dog's head will burn

Explanation:Solar winds are strongly destructive magnetically charged high energy winds. Satellite communication on earth and the occasional geomagnetic storm near the poles are the major disruptive effects caused by solar winds on earth.

Since solar winds are streams of charged particles released from the upperparts of the Sun, called the "corona". This plasma mainly consists of electrons, protons and alpha particles with kinetic energy between 0.5 and 10 keV. Instilled within the solar-wind plasma is the interplanetary magnetic field.

If the dog holds it's breath the heat wave would burn it's head but not outrightly because the breath has ceased for some seconds and it can't absorb the much heat of the solar wind into it's nostrils. The effect of holding its breath would still be disastrous but not as the first case.

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3000 N is exerted for 4.0 seconds on a 9500 kg object.<br><br> What is the change in momentum?
WARRIOR [948]
Force is the change in momentum over a specific time. The change of momentum is therefore the force multiplied by the time that the force acts, so 3000x4.0=12000 N s=12000 kg m/s
8 0
2 years ago
In the context of depth perception, which of the following is a monocular cue?
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8 0
3 years ago
A hammer has a mass of 1 kg. What is its weight (i) on Earth (ii) on the
solong [7]

Given mass= 1kg

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weight on outer space mg(gravity outer space = 0) = 0N

4 0
3 years ago
explain how metamorphic rocks are formed, and explain the differences between regional and contact metamorphism?
Igoryamba
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5 0
4 years ago
A force is applied to a block to move it up a 30° incline. The incline is frictionless, the block is initially at rest, F= 65.0
muminat

Answer:

0.96 m, upward

Explanation:

\theta=30^{\circ}

F=65 N

M=5 kg

Initial velocity, u=0

t=0.550 s

Fcos\theta-Mgsin\theta=Ma

Where g=9.8 m/s^2

Substitute the values

65cos30-5\times 9.8sin30=5a

31.8=5a

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Hence,the block moves upward because displacement is positive.

7 0
3 years ago
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