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Kruka [31]
3 years ago
13

g We saw in class that in a pendulum the string does no work. We also saw that the normal force does no work on an object slidin

g down a ramp. (a) Explain why the tension in the string of a pendulum does no work. (b) Explain why the normal force does no work on an object sliding down a ramp. (c) Give an example of a situation where tension does do work on an object. (d) Give an example of a situation where friction does positive work on something.
Physics
2 answers:
Ymorist [56]3 years ago
5 0

Answer:

From question (a) and (b) the pendulum motion is perpendicular to the force so the normal force will do no work and the tension in the string of the pendulum will not work

       i.e Normal \ Force(N)  = mg cos \theta

And \theta = 90 so

           N = 0

c

An example will be a where a stone is attached to the end of a string and is made to move in a circular motion while keeping the other end of the string in a fixed position        

d

A dog walking along a surface which has friction, here the frictional force would acting in the direction of the motion and this would do positive work  

Explanation:

atroni [7]3 years ago
5 0

Answer:

a) θ=90º, b) θ=90º, c) θ=0º W =F x, d) θ=180º W = -fr x

Explanation:

The job is defined by

       W = F. dx

Where the point is the dot product

      W = F dx cos θ

Let's apply this equation to our case

 

a) the attention is perpendicular to the arc of the displacement, and the displacement is parallel to the arc, so the angle between the tension and the displacement is 90º so the cosine is zero

        W = 0

b) The normal is the reaction to the weight of the body, so it is perpendicular to the surface and the displacement is parallel to the surface, the angle between these two is 90º

      W = 0

c) when we pull a body with a rope the tension of the rope does work on the body

         W = T x

d) When we pull a body on a rough surface, the friction force creates a job because it is the angle between friction and the 180º displacement

         W = - fr x

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A 10.0 m wire is hung from a high ceiling and held tightly below
yan [13]

Answer:

5 m

Explanation:

Speed of waves is as the product of frequency and wavelength hence expressed as s=fw where f is the frequency of waves in Hz, s is the speed in m/s and w is wavelength in meters.

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Substituting 335 m/s for s and 67 Hz for f then the wavelength is

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A metal block has a density of 5000 kg per cubic meter and a mass of 15,000 kg. What is its volume?
Naily [24]

Taking into account the definition of density, the volume of the metal block is 3 m³.

<h3>What is density</h3>

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

<h3>Volume of the metal block</h3>

In this case, you know that:

  • Density= 5000 \frac{kg}{m^{3} }
  • Mass= 15000 kg
  • Volume= ?

Replacing in the definition of density:

5000 \frac{kg}{m^{3} } =\frac{15000 kg}{volume}

Solving:

volume×5000 \frac{kg}{m^{3} }= 15000 kg

volume= \frac{15000 kg}{5000 \frac{kg}{m^{3} }}

<u><em>volume= 3 m³</em></u>

In summary, the volume of the metal block is 3 m³.

Learn more about density:

brainly.com/question/952755

brainly.com/question/1462554

#SPJ12

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