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3 years ago

Experiment: Limestone

1 answer:

7 0

When these bonds are destroyed, a reaction occurs. ... Vinegar reacting with limestone breaks the bonds of calcium carbonate and acetic acid.

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answer A vertical spring stretches 3.4 cm when a 8-g object is hung from it. The object is replaced with a block of mass 26 g th

victus00 [196]

Answer:

0.695s

Explanation:

From Hooke's law, the restoring force is given has

F = -ky .......1

Where F is the force, y is the spring displacement and k force constant of the spring.

Also recall,

F=mg ............ 2

Where m is the mass of object, g is the acceleration due to gravity.

Equating 1 and 2

Ky = mg

Given that g=9.8m/s2 , y is 3.4cm and g is 8g

K×3.4/100m =8/1000kg × 9.8m/s2

K= ( 0.008kg × 9.8m/s2 ) ÷ 0.034

K= 0.0784÷0.035

K=2.24N/m

Mass ofvthe second object is 25g =0.025kg

Period of oscillation T

T=2π√m/k

T=2×3.142√0.025/2.24

T=6.284√0.0111

T=0.659seconds

8 0

3 years ago

Read 2 more answers

Using component notation, enter the vector B⃗ B→B_vec in the answer box. Enter your answer as a pair of vector components, separ

Tomtit [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is $\vec B = 2, -3$

Explanation:

Looking at the graph in the diagram we see each unit is equal to 1 both in the x axis and in the y- axis

Now the value of B along the x axis is

$B_x = 2$

and along the y axis the value is

$B_y = -3$

Hence the vector B is

$\vec B =(B_x , B_y)= ( 2, -3)$

8 0

3 years ago

Development occurs:

Alex73 [517]

Answer:

Explanation:

4 0

2 years ago

What is the length of a pendulum that has a period of 0.500s?

anyanavicka [17]

That is the answer to your problem

7 0

3 years ago

When NASA was communicating with astronauts on the Moon, the time from sending on the Earth to receiving on the moon was 1.33 s.

frez [133]

To solve this problem it is necessary to apply the concepts related to the kinematic equations of movement description, which determine the velocity, such as the displacement of a particle as a function of time, that is to say

$v = \frac{x}{t}\rightarrow x = v*t$

Where,

x = Displacement

v = Velocity

t = Time

Our values are given as,

$v=3*10^8m/s$

$t = 1.33 s$

Replacing we have that,

$x=v*t$

$x=(3*10^8)(1.33)$

$x = 399'000.000m$

Therefore the distance from Earth to the Moon is 399.000 km

5 0

3 years ago