Pretty much, write two problems that equal to 0
Answer:
Is this an exam? looks like it
Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
Part 1) Find the area
we know that
The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle
so

we have that the base and the height of triangle is equal to the radius of the circle

substitute


simplify
Factor 36

Part 2) Find the perimeter
The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle
<em>The circumference of a quarter of circle is equal to</em>

substitute the given values


The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)


simplify

Find the perimeter

simplify
Factor 6

The answer is b
The perimeter of a rectangle is 2(l + w) so in this case, it is 2(15 + 9) and that is equal to 48. But so at c and d. So u need to multiply the width by 2 (9*2=18) and then you’ll see that 18-3=15. And therefore, the length is -5 and the width is 9
19.......................................