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3 years ago

Please help me with his question :)

Mathematics

1 answer:

Yuri [45]3 years ago

4 0

I’m pretty sure it’s the third option, Bella saves more per chore than Sweet T. If you replace the c in Bella’s equation with 1, it would be 3.5 times 1 which is 3.5 and then add 11 and it would be 14.5 which is more then Sweet T. You can do this with the rest of the numbers and Bella would still have more then Sweet T. Per chore

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Jean and Sarah are buying tubs of ice cream. 2 scoops of ice cream are twice the price of 1 scoop of ice cream. Jean buys 4 tubs

liberstina [14]

Answer:

The answer is below

Step-by-step explanation:

Let x represent the cost of 1 scoop of ice cream. Since the cost of 2 scoops of ice cream are twice the price of 1 scoop of ice cream, therefore the cost of 2 scoops of ice cream = 2x

Jean buys 4 tubs with 2 scoops in them and 2 tubs with 1 scoop each. Therefore the money spent by Jean is:

Money spent by Jean = 4(2x) + 2(x) = 8x + 2x = 10x

Sarah buys 2 tubs of 2 scoops and 4 tubs of 1 scoop. The money spent by Sarah is:

Money spent by Sarah = 2(2x) + 4(x) = 4x + 4x = 8x

Sarah spends 2.50 € less than Jean. Therefore:

Money spent by Sarah = Money spent by Jean - 2.5

8x = 10x - 2.5

2x = 2.5

x = €1.25

Therefore the cost of 1 scoop of ice cream is €1.25, the cost of 2 scoops of ice cream is €2.50.

Money spent by Jean = 10x = 10(1.25) = €12.5

Money spent by Sarah = 8x = 8(1.25) = €10

3 0

3 years ago

Can someone please explain to me how to do this.

JulijaS [17]

Y = x² - 4x + 4
y = 2x - 4

Find intersection of L and C:
x² - 4x + 4 = 2x - 4
x² - 6x + 8 = 0
 (x - 2)(x - 4) = 0
x = 2 or x = 4

When x = 2 , y = 2(2) - 4 = 0
When x = 4, y = 2(4) - 4 = 4

Points of intersection = A(2, 0) and B(4, 4)

Find the length of AB:

 $
\text {Length of AB}= \sqrt{(4-0)^2 + (4-2)^2} = \sqrt{16 + 4} = \sqrt{20} = 4.47 \text{ units}$

Answer: 4.47 units

4 0

3 years ago

. Evaluate the series 1 + 0.1 + 0.01 + . . .

EastWind [94]

We can employ a simple repeated decimal trick:

$x=1.111\ldots$

$0.1x=0.111\ldots$

$\implies x-0.1x=1\implies0.9x=1\implies x=\dfrac1{0.9}=\dfrac{10}9$

###

Alternatively, we can compute the partial sum of the series.

$\displaystyle S_n=\sum_{k=0}^n\dfrac1{10^k}$

$S_n=1+0.1+0.01+\cdots+\dfrac1{10^n}$

$0.1S_n=0.1+0.01+0.001+\cdots+\dfrac1{10^{n+1}}$

$\implies S_n-0.1S_n=0.9S_n=1-\dfrac1{10^{n+1}}$

$\implies S_n=\dfrac{10}9-\dfrac9{10^n}$

As $n\to\infty$ , the second term vanishes and we're left with $\dfrac{10}9$ . Notice that this is really just a more formal version of the earlier trick.