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kobusy [5.1K]
4 years ago
15

Evaluate the function, f(m) = 13 - 3m, when m is 4 f(4) = ​

Mathematics
2 answers:
qwelly [4]4 years ago
8 0

Answer:

1

Step-by-step explanation:

f(4)=13-3m (where m=4)

f(4)= 13-3×4

f(4)= 14-12

hence f(4)= 1

djverab [1.8K]4 years ago
7 0

Answer:

f(4)= 13-3(4)

4f= 13-12

4f=1

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Not skewed, I can tell dawgggg ooooohhhhh and I’m wasted
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3 years ago
1. Find the Least Common Multiple of these two monomials:<br> See picture
gtnhenbr [62]

Answer:

<em>The last choice is correct</em>

<em />LCM=120a^4b^7c^5<em />

Step-by-step explanation:

<u>Least Common Multiple (LCM)</u>

To find the LCM we can follow this procedure:

List the prime factors of each monomial.

Multiply each factor the greatest number of times it occurs in either factor.

We have two monomials:

12a^4b^2c^5

40a^3b^7c^1

The prime factors of the first monomial are:

2^2,3,a^4,b^2,c^5

The prime factors of the second monomial are:

2^3,5,a^3b^7c^1

LCM = Multiply 2^3*3*5*a^4*b^7*c^5

These are all the factors the greatest number of times they occur.

Operating:

LCM=8*15*a^4*b^7*c^5

\boxed{LCM=120a^4b^7c^5}

The last choice is correct

3 0
4 years ago
You are investing $5,000 and can invest for 2 years or 3 years at 1.75% and 1.25% interest rates, respectively. Which earns more
mart [117]

Answer:

You will make an earning of $1 million dollers

Step-by-step explanation:

7 0
3 years ago
I Need to find the Function Operations​
Alinara [238K]

Answer:

1) (f+g)(x)=2x^2+3x-6

2) (f-g)(x)=2x^2+x

3) (f \cdot g)(x)=2x^3-4x^2-9x+9

Step-by-step explanation:

So we have the two functions:

f(x)=2x^2+2x-3\text{ and } g(x)=x-3

And we want to find (f+g)(x), (f-g)(x), and (f*g)(x).

1)

(f+g)(x) is the same to f(x)+g(x). Substitute:

(f+g)(x)=f(x)+g(x)\\=(2x^2+2x-3)+(x-3)

Combine like terms:

=(2x^2)+(2x+x)+(-3-3)

Add:

=2x^2+3x-6

So:

(f+g)(x)=2x^2+3x-6

2)

(f-g)(x) is the same to f(x)-g(x). So:

(f-g)(x)=f(x)-g(x)\\=(2x^2+2x-3)-(x-3)

Distribute:

=(2x^2+2x-3)+(-x+3)

Combine like terms:

=(2x^2)+(2x-x)+(-3+3)

Simplify:

=2x^2+x

So:

(f-g)(x)=2x^2+x

3)

(f*g)(x) is the same to f(x)*g(x). Thus:

(f\cdot g)(x)=f(x)\cdot g(x)\\=(2x^2+2x-3)(x-3)

Distribute:

=(2x^2+2x-3)(x)+(2x^2+2x-3)(-3)

Distribute:

=(2x^3+2x^2-3x)+(-6x^2-6x+9)

Combine like terms:

=(2x^3)+(2x^2-6x^2)+(-3x-6x)+(9)

Simplify:

=2x^3-4x^2-9x+9

So:

(f \cdot g)(x)=2x^3-4x^2-9x+9

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3 years ago
1 and 1/2 divided by 4 and 2/8
Bumek [7]

Answer:

1.375

Step-by-step explanation:

3 0
3 years ago
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