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GalinKa [24]
3 years ago
13

What is 428÷7 what need help​

Mathematics
3 answers:
shtirl [24]3 years ago
8 0

Answer: <em>61.1428571429 </em>i think :)

DENIUS [597]3 years ago
3 0

Answer:

61.1428

Step-by-step explanation:

Brianna H2 years ago
0 0

61 with one left over.

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The answer is X=3 your welcome :)
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3 years ago
Please I need the answer very fast ​
tatyana61 [14]

Answer:

1 - cosΘ

Step-by-step explanation:

using the identity

sin²x + cos²x = 1 , then

sin²x = 1 - cos²x

\frac{sin^20}{1+cos0}

= \frac{1-cos^20}{1+cos0} ← factor 1 - cos²Θ as a difference of squares

= \frac{(1-cos0)(1+cos0)}{1+cos0} ← cancel 1 + cosΘ on numerator/ denominator

= 1 - cosΘ

7 0
2 years ago
to determine whether the inverse of a function is a function you can perform the horizontal line test, true or false
Svet_ta [14]
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3 0
3 years ago
Read 2 more answers
What to do when a negative number is subtracted from a positive number?
pentagon [3]
When you see the subtraction<span> (</span>minus<span>) sign followed by a </span>negative<span> sign, turn the two signs into a plus sign. Thus, instead of </span>subtracting<span> a </span>negative<span>, you're adding a </span>positive<span>, so you have a simple addition problem.</span>
5 0
3 years ago
to find the area of a trapezoid dylan uses the formula A=1/2 (B1+B2)h the bases have lengths of 3.6 cm and 12 1/3 cm. the height
Artemon [7]

Answer:

It is irrational because it can not be represented as a fraction of two integers

Step-by-step explanation:

Given

B_1 = 3.6

B_2 = 12\frac{1}{3}

H = \sqrt[3]5

Required

Why is the area irrational?

First, we need to calculate the area

Area = \frac{1}{2}(B_1 + B_2) * H

Area = \frac{1}{2}(3.6 + 12\frac{1}{3}) * \sqrt[3]5

Area = \frac{1}{2}(3.6 + \frac{37}{3}) * 17100

Area = \frac{1}{2}(\frac{10.8+37}{3}) * 1.710

Area = \frac{1}{2}(\frac{47.8}{3}) * 1.7100

Area = \frac{47.8}{6} * 1.7100

Area = \frac{47.8* 1.7100}{6}

Area = \frac{81.738}{6}

Area = 13.623

<em>It is irrational because it can not be represented as a fraction of two integers</em>

5 0
3 years ago
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