The answer is X=3 your welcome :)
Answer:
1 - cosΘ
Step-by-step explanation:
using the identity
sin²x + cos²x = 1 , then
sin²x = 1 - cos²x

=
← factor 1 - cos²Θ as a difference of squares
=
← cancel 1 + cosΘ on numerator/ denominator
= 1 - cosΘ
You can perform the horizontal line test on the original to see if the inverse will be a function. You will not perform the horizontal line test on the inverse.
When you see the subtraction<span> (</span>minus<span>) sign followed by a </span>negative<span> sign, turn the two signs into a plus sign. Thus, instead of </span>subtracting<span> a </span>negative<span>, you're adding a </span>positive<span>, so you have a simple addition problem.</span>
Answer:
It is irrational because it can not be represented as a fraction of two integers
Step-by-step explanation:
Given


![H = \sqrt[3]5](https://tex.z-dn.net/?f=H%20%3D%20%5Csqrt%5B3%5D5)
Required
Why is the area irrational?
First, we need to calculate the area

![Area = \frac{1}{2}(3.6 + 12\frac{1}{3}) * \sqrt[3]5](https://tex.z-dn.net/?f=Area%20%3D%20%5Cfrac%7B1%7D%7B2%7D%283.6%20%2B%2012%5Cfrac%7B1%7D%7B3%7D%29%20%2A%20%5Csqrt%5B3%5D5)







<em>It is irrational because it can not be represented as a fraction of two integers</em>