Hello there! Thank you for asking your question here at Brainly! I will be assisting you with answering this question today, and will be teaching you how to handle it on your own in the future.
First, let's take a look at our problem. "Twice a number and 5 more is 100." Based on this context, we are looking for a specific number to plug in.
To solve for this, I will rewrite the problem. As I do so, I will be writing (in parenthesis) the translation of an equation.
Twice a number (2x) and 5 more (+5) is 100 (=100).
This is our equation. To solve for this, we will need to do some basic algebra. Of course, I will teach you how to handle this on your own in future scenarios.
2x + 5 = 100 To solve for x, we need to isolate 2x, and then divide both sides by 2.
2x + 5 = 100 Subtract 5 from both sides to isolate 2x. 5 - 5 = 0 100 - 5 = 95
We now have the following equation: 2x = 95 Divide both sides by 2 to solve for x.
97.2% on the final. Find the total amount of points needed to get a 93%. 150+150+150+250 = 700 total points. 700*.93 = 651 total points needed to get 93%. find the points received from the other quizzes and subtract the sum from 651 to find how many points need to be scored on the final. 150*.88=132 (test 1) 150*.94=141 (test 2) 150*.90=135 (test 3) 132+141+135= 408
651-408 = 243 points to score on the final exam. 243/250 =.972 or 97.2%
