Answer:
The maximum mass that can fall on the mattress without exceeding the maximum compression distance is 16.6 kg
Explanation:
Hi there!
Due to conservation of energy, the potential energy (PE) of the mass at a height of 3.32 m will be transformed into elastic potential energy (EPE) when it falls on the mattress:
PE = EPE
m · g · h = 1/2 k · x²
Where:
m = mass.
g = acceleration due to gravity.
h = height.
k = spring constant.
x = compression distance
The maximum compression distance is 0.1289 m, then, the maximum elastic potential energy will be the following:
EPE =1/2 k · x²
EPE = 1/2 · 65144 N/m · (0.1289 m)² = 541.2 J
Then, using the equation of gravitational potential energy:
PE = m · g · h = 541.2 J
m = 541.2 J/ g · h
m = 541.2 kg · m²/s² / (9.8 m/s² · 3.32 m)
m = 16.6 kg
The maximum mass that can fall on the mattress without exceeding the maximum compression distance is 16.6 kg.
We will use two definitions to solve this problem. The first will be given by the conservation of energy, whereby the change in kinetic energy must be equivalent to work. At the same time, work can be defined as the product between the force by the distance traveled. By matching these two expressions and clearing for the Force we can find the desired variable.
Thus the force acting on the sled is,
Replacing,
Therefore the Force acting on the sled is 32N
Answer:
The average velocity of Samuel’s entire trip is 1.16 m/s.
Explanation:
Given:
Distance covered at first checkpoint (d₁) = 925 m
Distance covered at second checkpoint (d₂) = 673 m
Time taken for reaching first checkpoint (t₁) = 10 min = 10 × 60 = 600 s [∵1 min = 60 s]
Time taken for reaching second checkpoint (t₂) = 13 min = 13 × 60 = 780 s
Now, the average velocity of Samuel's entire trip is given by the formula:
Total distance traveled is equal to the sum of the distances traveled at first and second checkpoints. So,
Total distance covered =
Total time taken =
Therefore, the average velocity is given as:
Hence, the average velocity of Samuel’s entire trip is 1.16 m/s.
The formula for centripetal acceleration is v^2/r, where v is the tangential velocity, and r is the radius.
<span>Alternatively, w^2r where w is the angular velocity and r is the radius.
</span><span>The centripetal acceleration is ar=(((1.70 rev/s)*(2*pi rad/rev))^2)*(0.132m)= 15.06 m/s^2 </span>
Answer:
Object B has greater density
desity A=20/10=2 g cm^-3 . density B=50/10=5 g cm^-3
the object that has greater mass has the greater density because the volume of the those two objects are same