Answer:0.27
Explanation:
Given
One worker Pushes with force 
other Pulls it with a rope of rope 
mass of crate 
both forces are horizontal and crate slides with a constant speed 
Both forces are in the same direction so Friction will oppose the forces and will be equal in magnitude of sum of two forces because crate is moving with constant speed i.e. net force is zero on it 

where  is the friction force
 is the friction force



where  is the coefficient of static friction
is the coefficient of static friction



 
        
             
        
        
        
Answer:
Explanatioyour answers look right, but if there has , has to be another answer its a , but your answers are right
 
        
                    
             
        
        
        
Answer:
 1.08
Explanation:
This is the case of interference in thin films in which interference bands are formed due to constructive interference of two reflected light waves , one from upper layer and the other from lower layer . If t be the thickness and μ be the refractive index then 
path difference created will be 2μ t. 
For light coming from rarer to denser medium , a phase change of π occurs additionally after reflection from denser medium, here, two times, once from upper layer and then from the lower layer ,  so for constructive interference 
path diff = nλ , for minimum t , n =1
path diff = λ
2μ t. =  λ
μ = λ / 2t
= 626 / 2 x 290
= 1.08 
 
        
             
        
        
        
Answer:5250 N
Explanation: ig:iihoop.vince 
 
        
             
        
        
        
Answer:
The average velocity of the sled is vavg = s/t.
Explanation:
Hi there!
The average velocity is calculated as the traveled distance over time:
vavg = Δx/Δt
Where:
vavg = average velocity.
Δx = traveled distance.
Δt = elapsed time.
We already know the traveled distance (s) and also know the time it takes the sled to travel that distance (t). Then, the average velocity can be calculated as follows:
vavg = s/t
Have a nice day!