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3 years ago

What elemental classification does oxygen belong to?

2 answers:

6 0

The elemental classification for oxygen would be non-metal. It is located in period number 2 and group number 16. It has an atomic number of 8. At room temperature, it exists as a gas. Hope this answers the question. Have a nice day.

Komok [63]3 years ago

3 0

Answer: Oxygen is a non-metal.

Explanation:

Elements are distributed into 7 period and 18 Groups in a periodic table.

Elements are classified into three categories:

Metals: They are called as metals because they loose electrons to attain stability. These elements belong from Group 1 to group 13 of the periodic table. They are hard and are mainly solid.
Non-metals: They are called as non-metals because they gain electrons to attain stability. These elements belong from Group 15 to group 17 of the periodic table. They are soft and are mainly liquid or gases.
Metalloids: They are called as metalloids because they show properties of both metals and non-metals. These elements belong from Group 14 of the periodic table.

Oxygen belongs to Group 16 and period 2 of the periodic table.

Hence, oxygen is a non-metal.

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A thermally isolated system is made up of a hot piece of aluminum and a cold piece of copper; the aluminum and the copper are in

Illusion [34]

Answer:

Copper is the object that experiences the greater temperature change.

Explanation:

Thermally isolated system means that the system does not exchange thermal energy with the surroundings.

Hence, any thermal exchange, in virtue of the temperature difference of the aluminum and copper pieces, is between them.

In consequence, the law of conservation of energy states that the heat lost by the hot substance will be gained by the cold matter.

In equations, that is:

Heat lost by aluminum = heat gained by copper.

Now, the gain or loss or heat of a substance, Q, is related with the mass (m), the specific heat (Cs), and the cahnge of temperature (ΔT), per the equation:

Q = m × Cs × ΔT

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[m × Cs × ΔT ] aluminum = [m × Cs × ΔT ] copper.

Under the reasoning assumption that the masses of aluminum and copper are equal, the equations is simplified to:

[Cs × ΔT ] aluminum = [Cs × ΔT ] copper.

Cs aluminum / Cs copper = ΔT copper / ΔT aluminum

Cs aluminum > 2 × Cs copper ⇒ Cs

Cs aluminum / Cs copper > 2 ΔT copper / ΔT aluminum

ΔT copper / ΔT aluminum > 2

ΔT copper > 2 × ΔT aluminum

In words, since it is stated that the specific heat of aluminum is more than double that of copper, in order to keep the equality, ΔT of copper shall be more than double ΔT of aluminum.

Hence, the conclusion is that the object that experiences the greater temperature change is copper (the one with the lower specific heat), under the assumption that both objects have the same amount of matter (mass).

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Answer:

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