Answer:
23.8
Explanation:
Formula
weight % = weight of solute/ weight of solution x 100
weight of solution = weight of salt + weight of water
weight of solution = 1.62 lb + 5.20 lb = 6.82 lb
weight % = 1.62 / 6,82 x 100
weight % = 0.238 x 100
weight % = 23.8
Answer:
6.93
Explanation:
Step 1: Given data
- Standard Gibbs free energy (∆G°): -5.20 kJ
- Equilibrium constant (K): ?
Step 2: Convert the temperature to the Kelvin scale
We will use the following expression.
K = °C + 273.15
K = 50°C + 273.15
K = 323 K
Step 3: Calculate K
We will use the following expression.
∆G° = -R × T × ln K
-5.20 × 10³ J = -(8.314 J/mol.K) × 323 K × ln K
K = 6.93
<u>Answer:</u> The new volume of the balloon will be 583.5 L
<u>Explanation:</u>
To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.
The equation follows:
where,
are the initial pressure, volume and temperature of the gas
are the final pressure, volume and temperature of the gas
We are given:
![P_1=1.15atm\\V_1=3.60L\\T_1=20^oC=[20+273]K=293K\\P_2=5.40\times 10^{-3}atm=0.00540atm\\V_2=?\\T_2=-50^oC=[-50+273]K=223K](https://tex.z-dn.net/?f=P_1%3D1.15atm%5C%5CV_1%3D3.60L%5C%5CT_1%3D20%5EoC%3D%5B20%2B273%5DK%3D293K%5C%5CP_2%3D5.40%5Ctimes%2010%5E%7B-3%7Datm%3D0.00540atm%5C%5CV_2%3D%3F%5C%5CT_2%3D-50%5EoC%3D%5B-50%2B273%5DK%3D223K)
Putting values in above equation, we get:
Hence, the new volume of the balloon will be 583.5 L
