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3 years ago

10

Describe the relationship between a hypothesis, a theory, and a natural law.

1 answer:

adell [148]3 years ago

8 0

Hypothesis, theory and natural laws are related in a number of ways, the connections are as follows:
1. A THEORY is a human attempt at describing a NATURAL LAW.
2. THEORIES usually begin as HYPOTHESIS.
3. NATURAL LAWS are discovered through experiments and HYPOTHESIS is a major part of every scientific experiments.

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Cesium has a radius of 272 pm and crystallizes in a body-centered cubic structure. What is the edge length of the unit cell

olchik [2.2K]

Answer: Edge length of the unit cell = 628pm

Explanation: For a body centred cubic structured system, the relationship between the edge length of the unit cell and radius of the atoms in the structure is

Edge length of Unit cell (a) = (4R)/(√3)

R = 272pm = (272 × (10^-12))m = (2.72 × (10^-10))m

a = (4 × (2.72 × (10^-10)))/(√3)

a = (6.28157 × (10^-10))m = 628pm

4 0

3 years ago

What is the mass of an object with a density of 3.4 g/mL and a volume of 500.0 mL

umka2103 [35]

Formula:
$mass=density *volume$

Given:
Density=3.4
Volume=500.0

Plug them into the formula:
$mass=3.4 *500.0=1700$

Final answer: 1700g

5 0

3 years ago

How many milliliters of 0.0896M LiOH are required to titrate 25.0 mL of 0.0759M HBr to the equivalence point?

slavikrds [6]

Answer:

$V_{LiOH}=21.8mL$

Explanation:

Hello,

In this case, during titration at the equivalence point, we find that the moles of the base equals the moles of the acid:

$n_{LiOH}=n_{HBr}$

That it terms of molarities and volumes we have:

$M_{LiOH}V_{LiOH}=M_{HBr}V_{HBr}$

Next, solving for the volume of lithium hydroxide we obtain:

$V_{LiOH}=\frac{M_{HBr}V_{HBr}}{M_{LiOH}} =\frac{0.0759M*25.0mL}{0.0896M} \\\\V_{LiOH}=21.8mL$

Best regards.

8 0

2 years ago

Alex73 [517]

Answer:

I think it 28.8

Explanation:

am not sure

5 0

3 years ago

Help please chemistry will give brainliest

Jlenok [28]

Answer:

Explanation:

The Ideal Gas Law states that PV=nRT.

Rearrange that into P/n=RT/V.

In this case, the cylinder is rigid so the volume, V, does not change.

Temperature does not change either.

Out of 450 grams of gas, 150 grams leak out. So only 450-150 = 300 grams is left.

n is number of moles which is dependent on mass:

n1/n2 = 450/300 = 3/2

P1/n1 = RT/V = P2/n2

P2 = P1/n1*n2

= 7.2/3*2

= 4.8 atmosphere

6 0

3 years ago

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