The formula for specific gravity is:
where 
is the density of the substance and 
is the density of water.
The density of water, = 
Substituting the values in above formula we get,
The formula of density is:
The density of mercury is 
The mass of mercury is 
Substituting the values in density formula:
Answer:
V₂ = 4.34 L
Explanation:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
Given data:
Initial volume = 3.50 L
Initial pressure = 150 Kpa (150/101.325 = 1.5 atm)
Initial temperature = 330 K
Final temperature = 273 K
Final volume = ?
Final pressure = 1 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1.5 atm × 3.50 L × 273 K / 330 K × 1 atm
V₂ = 1433.3 atm .L. K / 330 k.atm
V₂ = 4.34 L
John Dalton was the first scientist
"<span>using shaving cream, rather than shaving on dry skin" I believe this is the answer. coz rest of them would increase friction rather than decrease</span>
Answer:
Acetylide , Enol ,aldehydes, tautomers, alkynes , Hydroboration, Keto
Explanation:
Reset <u>Acetylide</u> anions are strong nucleophiles that open epoxide rings by an SN2 mechanism. <u>Enol </u>tautomers have an O-H group bonded to a C=C. <u>aldehydes </u>are formed from terminal alkynes with the addition of water using BH3 then H2O2. <u>tautomers</u> are constitutional isomers that differ in the location of a double bond and a hydrogen and exist in an equilibrium with each other. <u>alkynes</u> are compounds that contain a carbon-carbon triple bond. <u>Hydroboration</u> of a terminal alkyne adds BH₂ to the less substituted, terminal carbon.<u> Keto</u> tautomers have a C=O and an additional C-H bond.
