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Sholpan [36]
3 years ago
15

The number of O atoms in 6.15 g of Al(PO 4 ) 3 (molar mass=122.00 g/mol) is

Chemistry
1 answer:
pickupchik [31]3 years ago
6 0
Soowowowowlw,was the day that I was just trying to find out
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answer is A. a saturated hydrocarbon that has more than 35 carbons in its chain

Explanation:

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Explain the reaction of metals with water.<br><br>​
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it rusts

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When a sample of aqueous hydrochloric acid was neutralized with aqueous sodium hydroxide in a calorimeter, the temperature of 10
Annette [7]
<span>6.50x10^3 calories. Now we have 4 pieces of data and want a single result. The data is: Mass: 100.0 g Starting temperature: 25.0°C Ending temperature: 31.5°C Specific heat: 1.00 cal/(g*°C) And we want a result with the unit "cal". Now you need to figure out what set of math operations will give you the desired result. Turns out this is quite simple. First, you need to remember that you can only add or subtract things that have the same units. You may multiply or divide data items with different units and the units can combine or cancel each other. So let's solve this: Let's start with specific heat with the unit "cal/(g*°C)". The cal is what we want, but we'ld like to get rid of the "/(g*°C)" part. So let's multiply by the mass: 1.00 cal/(g*°C) * 100.0 g = 100.0 cal/°C We now have a simpler unit of "cal/°C", so we're getting closer. Just need to cancel out the "/°C" part, which we can do with a multiplication. But we have 2 pieces of data using "°C". We can't multiply both of them, that would give us "cal*°C" which we don't want. But we need to use both pieces. And since we're interested in the temperature change, let's subtract them. So 31.5°C - 25.0°C = 6.5°C So we have a 6.5°C change in temperature. Now let's multiply: 6.5°C * 100.0 cal/°C = 6500.0 cal Since we only have 3 significant digits in our least precise piece of data, we need to round the result to 3 significant figures. 6500 only has 2 significant digits, and 6500. has 4. But we can use scientific notation to express the result as 6.50x10^3 which has the desired 3 digits of significance. So the result is 6.50x10^3 calories. Just remember to pay attention to the units in the data you have. They will pretty much tell you exactly what to add, subtract, multiply, or divide.</span>
4 0
3 years ago
Compare the entry-level substrates, products, and metabolic purposes of glycolysis and gluconeogenesis.
mixas84 [53]
Glycolysis is the process by which glucose molecules are broken down to pyruvate molecules while gluconeogenesis is the process by which glucose is synthesized from non-carbohydrate molecules. For glycolysis, the entry level substrate is glucose, the product is pyruvate and energy in form of ATP and the metabolic purpose of glycolysis is energy production. For gluconeogenesis, the entry level substrate can be lactate, pyruvate, glycerol or glucogenic amino acid, the product is glucose and the purpose of the process is generation of glucose.
3 0
3 years ago
Which are the products in this chemical reaction? 2C4H10 + 13O2 8CO2 + 10H2O A. 13O2 + 10H2O B. 8CO2 + 10H2O C. 2C4H10 + 13O2 D.
arsen [322]

<u>Answer:</u> The products in the given chemical reaction are 8CO_2\text{ and }10H_2O

<u>Explanation:</u>

Reactants are defined as the species which react in the reaction and are written on the left side of the reaction arrow.

Products are defined as the species which are produced in the reaction and are written on the right side of the reaction arrow.

For the given chemical equation:

2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O

The reactants of the above reaction are 2C_4H_{10}\text{ and }13O_2 and the products are 8CO_2\text{ and }10H_2O

Hence, the products in the given chemical reaction are 8CO_2\text{ and }10H_2O

8 0
3 years ago
Read 2 more answers
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