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Afina-wow [57]
3 years ago
7

If the statement is true, select True. If it is false, select False.

Chemistry
1 answer:
Marianna [84]3 years ago
7 0

This statement is true

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A chemical reaction produces 653 550 kj of energy as heat in 142.3min. calculate the rate of energy transferred in kj per minute
miskamm [114]

We have the value of  

Total energy produced in the chemical reaction=653 550 KJ  

Time needed=142.3min  

To calculate the rate of energy transfer, that is the amount of energy produced per minute.  

Rate of energy transfer=\frac{Total energy produced}{Time needed}

=\frac{653 550}{142.3}

=4592.76 KJ min⁻¹

So, the rate of energy transfer is 4592.76 KJ min⁻¹.

6 0
3 years ago
What is the difference between liquid nitrogen and nitrogen gas​
Studentka2010 [4]

Answer:

The difference between liquid nitrogen and nitrogen gas is liquid nitrogen gas is man made or caused by humans but, nitrogen gas takes place naturally in the earths atmosphere.

Explanation:

Hope this helps :)

8 0
3 years ago
2. (10 Points) If the experiment had continued with you adding an 8 kg weight to
vaieri [72.5K]

Answer: picture is work for # 1,2,4,5,7

Explanation: number 3: as the pressure in the volume decreases, the volume increases causing it to expand and eventually blow.

number 6: because the temperature and the amount of gas don’t change, these terms don’t appear in the equation. What Boyle’s law means is that the volume of a mass of gas is inversely proportional to its pressure. This linear relationship between pressure and volume means doubling the volume of a given mass of gas decreases its pressure by half.

hope this helps :))

4 0
3 years ago
How many grams of O2(g) are needed to completely burn 15.6 g of C3H8(g)?
alexdok [17]
15.6gC3H8*44.1gC3H8*32gO2=11.32
7 0
4 years ago
A gas occupies 2.0 m3 at 100.0k and exerts a pressure of 100.0kPa. What volume will the gas occupy if the temperature is increas
Svetradugi [14.3K]
According to ideal gas equation, we know for 1 mole of gas: PV=RT
where P = pressure,  T = temperature, R = gas constant, V= volume
If '1' and '2' indicates initial and final experimental conditions, we have
\frac{P1V1}{P2V2} =  \frac{T1}{T2}

Given that: V1 = 100.0 kPa, T1 = 100.0 K, V1 = 2.0 m3, T2 = 400 K, P2 = 200.0 kPa

∴ on rearranging above eq., we get V2 = \frac{P1V1T2}{T1} =  \frac{100 X 2 X 400}{200X100}
∴ V2 = 4 m3 
7 0
3 years ago
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