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3 years ago

Which compound will have the most polarization?

Chemistry

1 answer:

frosja888 [35]3 years ago

6 0

Answer:

Option D. Magnesium oxide.

Explanation:

The <em>polarization</em> of a compound is determined by the formation of dipoles which is the result of the difference in electronegativities between the bonds.

Since all the compounds are with magnesium, you can use the periodic trend of the other elements, i.e. tellurium, selenium, sulfur and oxygen to determine which one has the most electronegativiy difference when bonded to magnesium.

Oxygen, sulfur, selenium, and tellurium are all in the same group of the periodic table, group 16.

In a group the electronegativy decreases when you move down the grpup, so the most electronegative of all those four elements is oxygen.

Now you can conclude that the compound of magnesium with oxygen, magnesium oxide (option D), will be have the most polarization of the four given compounds.

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Octanol is slightly soluble in water, and water is very soluble in octanol. why is it important to presaturate octanol with wate

notsponge [240]

N-Octanol and water are chosen because the connection between a substance's hydrophilicity and lipophilicity is measured by $K_{OW}$ (n-Octanol/Water partition coefficient). When a chemical is more dissolves in fat-like solvents like n-octanol, the value is more significant than one, when it's more dissolved in water, the value is lower.

What is the partition coefficient?

The partition coefficient for the two-phase network comprising n-octanol and water is known as the $K_{OW}$ value. N-Octanol-Water Partition Ratio is another name for it.

The connection between a substance's hydrophilicity (its ability to dissolve in water) and lipophilicity (its ability to dissolve in fat) is measured by $K_{OW}$ . The value is bigger if a drug is more accessible in fat-like liquids like n-octanol and less if a compound seems more water-soluble.

Owing to linkage or fragmentation, substances that are involved in the octanol-water combination as multiple synthetic entities are each given a unique $K_{OW}$ ratio.

So, N-Octanol is chosen because it has a carbon/oxygen ratio that is comparable to that of lipids and because it shows both hydrophobic and hydrophilic properties. N-octanol, therefore, resembles the makeup and characteristics of cells and other living things.

Learn more about octanol here:

brainly.com/question/7768749

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8 0

8 months ago

Calculate the [H3O+] for orange juice, which has a [OH–] = 5.0 × 10–11 M.

zloy xaker [14]

Answer:

i Think.... i think its a carrot

Explanation: 5.0 x 10-11 M

3 0

2 years ago

Match the following words with their definitions.

exis [7]

Answer: there is nothing there to answer

Explanation:

5 0

2 years ago

Select the correct answer.

Minchanka [31]

Answer:

A. it is the lowest at low temperatures

Explanation:

It is true with respect to the kinetic energy of a molecule that the it is the lowest at low temperatures.

The kinetic energy of a molecule is the energy due to the motion of the particles within a substance.

Kinetic energy is directly proportional to the temperature of a substance.
The higher the temperature, the more the kinetic energy of the molecules within a system.
At low temperature, kinetic energy is the lowest.
At the highest temperature, kinetic energy is the highest

3 0

3 years ago

Read 2 more answers

If the metal in the ionic compound is a transition element (with variable charge metal ions), the ionic charge is written as a R

spayn [35]

Answer : The name of ionic compound is, Copper(II) fluoride.

Explanation :

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

The nomenclature of ionic compounds is given by:

1. Positive ion is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.

$CuF_2$

$CuF_2$ is an ionic compound because copper element is a metal and fluorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The oxidation state of copper in $CuF_2$ is, (+2)

Thus, the name of ionic compound is, Copper(II) fluoride.

8 0

2 years ago