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yaroslaw [1]
3 years ago
13

Point P(−3, −4) is rotated 90° counterclockwise about the origin. What are the coordinates of its image after this transformatio

n? Enter your answer in the boxes.
Mathematics
2 answers:
SpyIntel [72]3 years ago
6 0

Answer: The co-ordinates of the point P after transformation are (4, -3).

Step-by-step explanation:  Given that a point P(-4, -3) is rotated Point P(−3, −4) is rotated 90° counterclockwise about the origin.

We are given to find the co-ordinates of its image after the transformation.

We know that,

If a point (x, y) is rotated 90° counterclockwise about the origin, then its co-ordinates after the transformation becomes

(x, y)  ⇒  (-y, x).

Therefore, if P changes to P' after the transformation, then co-ordinates of the point P' will be

P(-3, -4)  ⇒  P'(4, -3).

Thus, the co-ordinates of the point P after transformation are (4, -3).

andreyandreev [35.5K]3 years ago
3 0

The 90° CCW transformation is

... (x, y) ⇒ (-y, x)

For your point, this is ...

... (-3, -4) ⇒ (-(-4), -3) = (4, -3)

___

What boxes?

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A polynomial function of least degree with integral coefficients that has the

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So zeros are 3i, -3i, 0 and -1

Now we write the zeros in factor form

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the factor form of given zeros

\:\left(x-3i\right)\left(x-\left(-3i\right)\right)\left(x-0\right)\left(x-\left(-1\right)\right)\\\left(x-3i\right)\left(x+3i\right)\left(x-0\right)\left(x+1\right)

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x\left(x-3i\right)\left(x+3i\right)\left(x+1\right)\\x\left(x^2+9\right)\left(x+1\right)\\x\left(x^3+x^2+9x+9\right)\\x^4+x^3+9x^2+9x

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