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nalin [4]
3 years ago
11

Which expression is equivalent to 2(3−4)−(8+3)?

Mathematics
2 answers:
horrorfan [7]3 years ago
7 0

Answer:

-13

Step-by-step explanation:

2(3-4)-(8+3)

2(-1)-(11)

-2-(11)

=-13

Korvikt [17]3 years ago
3 0

Answer:20

Step-by-step explanation:

2(3-4)-(8+3)                                                                                                                                  

2(1)-(11)

2-22

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Which graph is right?
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B

Step-by-step explanation:

A "or equal to" sign always contains a black colored in circle... With it's pointy end pointing at which direction it is being located.

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3 years ago
If the center of a circle is<br> (-5,8) and a point on the circle is (-5, -4) What is the radius?
Maslowich

Answer:

The radius is 12.

Step-by-step explanation:

You're given the center and a point on the circle. The point and the center both have an x-coordinate of -5, so there is no horizontal distance between them. The distance is only in the vertical direction. The distance from 8 to -4 is 12. Since this is the distance from the center to a point on the circle, this equals the radius.

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3 years ago
An uber in Los Angeles charges $3.50 per mile and $2 for every person. If taxi cab ride for three people costs $20, how far did
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Step-by-step explanation:

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lauren is 4 years older than cole. their mom is 7 years older than triple coles age. the sum of the ages of cole, lauren, and th
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Step-by-step explanation:

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5 0
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Read 2 more answers
(12x + y + z = 26
mel-nik [20]

Option D. D has the matrix of constants [[12], [11], [4]].

Step-by-step explanation:

Step 1:

With the given equations, we can form matrices to represent them.

The coefficients of x, y, and z form a matrix of order 3 ×3, the variables x, y, and z form a matrix of order 1 ×3 and the constants form a matrix of order 1 ×3.

Step 2:

The linear system A is represented as

\left[\begin{array}{ccc}12&1&1\\1&-11&0\\1&-1&4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}26\\17\\23\end{array}\right].

Step 3:

The linear system B is represented as

\left[\begin{array}{ccc}4&1&1\\1&-11&0\\1&-1&12\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}23\\17\\26\end{array}\right].

Step 4:

The linear system C is represented as

\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}4\\11\\12\end{array}\right].

Step 5:

The linear system D is represented as

\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}12\\11\\4\end{array}\right].

Step 6:

Of the four options, the linear system D has the matrix of constants [[12], [11], [4]]. So the answer is option D. D.

4 0
3 years ago
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