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2 years ago

Need help on 9, 10, 11

Mathematics

1 answer:

Dafna1 [17]2 years ago

6 0

Answer:

Step-by-step explanation:

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A sphere with a radius of 4mm how do i find the answer

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Answer:

201.06

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3 years ago

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If the area of the triangle (the shaded portion below) within the pentadecagon is 10 units, what is the area

GaryK [48]

Answer:

150

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3 years ago

Please help me with the below question.

VMariaS [17]

By letting

$y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}$

we get derivatives

$y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}$

$y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}$

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

$5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0$

Examine the lowest degree term $\left(x^{r-1}\right)$ , which gives rise to the indicial equation,

$5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0$

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients $c_k$ is

$(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}$

so that with r = 4/5, the coefficients are governed by

$c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}$

c) Starting with $c_0=1$ , we find

$c_1 = -\dfrac{c_0}5 = -\dfrac15$

$c_2 = -\dfrac{c_1}{10} = \dfrac1{50}$

so that the first three terms of the solution are

$\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}$

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1 year ago

The ratio between the length and the breadth of the park is 3:2. if a man cycling along the boundary of the park at the speed 12

Ilia_Sergeevich [38]

D is answer.
Perimeter is 2x +3x +2x + 3x = 10x where x is unknown factor of distance.
So P = 10x
Velocity is 12 km/hr = .2 km/min
P =1.6 Km = 10x
x= .16 Km 3x = .48 km, 2x=.32 km
Area = .48 X .32 Km^2
= 153600 m^2

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2 years ago

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Sonja's house is 4 blocks west and 1 block south of the center of town. Her school is 3 blocks east and 2 blocks north of the ce

dexar [7]

If the center of town is the origin then 4 blocks west and 1 block south would be 4 blocks to the left and 1 block down or (-4, -1) house 3 block east and 2 blocks north would be 3 blocks to the right and 2 blocks up or (3, 2) use the distance formula to find the distance between two points. That's all I know! hope this helps!~ just remember to use the distance formula to find the distance between two points.

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2 years ago

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