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kvasek [131]
3 years ago
12

9. Five times a number is the same as the number added to five. What is the number?

Mathematics
1 answer:
Alenkinab [10]3 years ago
4 0
Let x be the number

5x = x + 5

subtract x from both sides

5x - x = 5

4x = 5

Divide both sides by 4

4x/4 = 5/4

x = 5/4

=======

Check:

5 * (5/4) = (5/4) + 5

25/4 = 1.25 + 5

6.25 = 6.25





Hope it helps . Note that I am a sixth grade student and I don’t know anything . I got help from somebody
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The answer would be 16.
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Help 30 points and i will mark brainliest for the best answer which will be more points
klasskru [66]

Answer:

See below

Step-by-step explanation:

From the table we see there is a relation between x and y values

Every step change of x = 0.5, every step change of y = 2

<u>This relation is linear. The formula for linear function is:</u>

  • y = mx + b

<u>Using to pairs of points to get the slope and y-intercept</u>

  • (0, 60) and (1, 64)

<u>Calculating the slope:</u>

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<u>So the function is</u>

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<h3>Part A</h3>
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<h3>Part B</h3>
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10 oranges cost Php 120 ,how much 35 oranges cost?​
ValentinkaMS [17]
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A box contains 20 lightbulbs, of which 5 are defective. If 4 lightbulbs are picked from the box randomly, the probability that a
madam [21]

Answer:

Option D. 938/969

Step-by-step explanation:

At most 2 defective means 2 or less than 2 bulbs are defective

So, we have 3 cases:

a) No defective bulb.       b) 1 defective bulb.      c) 2 defective bulbs

Case a) No defective bulb

Total number of bulbs = 20

Number of defective bulbs = 5

Number of non-defective bulbs = 15

Total number of ways to select 0 defective bulb = 15C4 = 1365

Case b) 1 defective bulb

Total number of ways to select 1 defective bulb = 15C3 x 5C1 = 2275

Case c) 2 defective bulbs

Total number of ways to select 2 defective bulbs = 15C2 x 5C2 = 1050

Therefore, total number of ways to select at most 2 defective bulbs = 1365 + 2275 + 1050 = 4690

Total number of ways to select 4 bulbs from 20 = 20C4 = 4845

Therefore, probability of selecting at most 2 defective bulbs = \frac{4690}{4845}=\frac{938}{969}

Therefore, option D gives the correct answer.

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